Answer:
The product would have more acidity than Diethyl malonate
Explanation:
For this question, first, we have to start with the structure of the bromination reaction. <u>The bromination would add a "Br" atom</u> in the middle carbon between the ester groups. Therefore, the molecule produced would be <u>diethyl 2-bromomalonate</u> and the formula of this compound fits with the reported by the question: ![C_7H_1_1BrO_4](https://tex.z-dn.net/?f=C_7H_1_1BrO_4)
Now, if we have to analyze the acidity we have to check the <u>most acidic hydrogen</u>. In this case, is the "H" in the middle carbon (red hydrogen). In the Diethyl malonate, we have an <u>inductive effect</u> caused by the carbonyl groups on each side of the middle carbon. In the diethyl 2-bromomalonate, we have this same inductive effect plus the Br atom bonded to the same carbon. Therefore, would be <u>easier to remove the hydrogen</u>. So, diethyl 2-bromomalonate would ba more acidity than Diethyl malonate.
See figure 1
I hope it helps!
HCO3^1- because sodium has a 1+ charge
Answer:
They will repel each other.
Explanation:
According to Coulomb's law, the force between two chargee is directly proportional to the product of the magnitude of the both charges and inversely proportional to their distance apart.
The force of attraction between electric charges may be attractive or repulsive in nature. When two negative charges are placed in close proximity to each other, they repel each other because like charges repel each other.
The Arrhenius theory of acids and bases states that “an acid generates H+ ions in a solution whereas a base produces an OH– ion in its solution”. The Bronsted-Lowry theory defines “an acid as a proton donor and a base as a proton acceptor