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3 years ago

Math help mee plzzzzzz

Mathematics

1 answer:

Alisiya [41]3 years ago

4 0

The answer would be answer.

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The hardware store where you work charge 80 cents including tax, for a pound of nails. A customer purchases 5 3/4 pound of nails

Sophie [7]

Answer:

$4.60

Step-by-step explanation:

1 lb ---> 80 cents

5 3/4 lb ---> 5 3/4 * 80 cents

$5 \dfrac{3}{4} \times 80 =$

$= \dfrac{23}{4} \times \dfrac{80}{1}$

$= \dfrac{23 \times 80}{4 \times 1}$

$= \dfrac{1840}{4}$

$= 460$

460 cents = $4.60

5 0

2 years ago

Read 2 more answers

Sue chooses a dress to wear when she goes out with her parents, but she can wear it only if her parents approve. The probability

Sophie [7]

12%

40% = 0.4
30 = 0.3

0.3 x 0.4 = 0.12

0.12 = 12%

4 0

2 years ago

Find the value of x and the value of y

Doss [256]

Answer:

Step-by-step explanation:

These sides are in a ratio:

$1 : 2 : \sqrt{x} 3$

Therefore:

6 0

2 years ago

Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the

Likurg_2 [28]

Answer:

(a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, $P(X)=\frac{1}{6}$

(a) Moment generating function can be written as $M_{x}(t)$ .

$M_x(t)=\sum_{x=1}^{6} P(X=x)$

$M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}$

$M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) Now, find $E(X) \text { and } E\((X^{2})$ using moment generating function

$M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)$

$M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)$

$\Rightarrow E(X)=\frac{21}{6}$

$M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)$

$M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)$

$\Rightarrow E\left(X^{2}\right)=\frac{91}{6}$

Hence, (a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$ .

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

6 0

3 years ago

How do solve this problem 2/3 (2/8 + 4/8) =

scoundrel [369]

Answer:

1/2

Step-by-step explanation:

2/3 (2/8 + 4/8) =

First simplify what is inside the parentheses

2/8+4/8 = 6/8

Replace with 6/8

2/3 (6/8) =

Then multiply

2*6 =12

3*8 = 24

12/24

Divide top and bottom by 12

1/2

6 0

3 years ago

Read 2 more answers