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1 year ago

One factor of the polynomial is . which expression represents the other factor, or factors, of the polynomial?

Mathematics

2 answers:

stich3 [128]1 year ago

7 0

Your question was incomplete. Please refer the content below:

One factor of a polynomial is (x+1) . which expression represents the other factor, or factors, of the polynomial 2 x² + 3 x + 1 ?

We get that if one factor of the polynomial 2 x² + 3 x + 1 is (x+1), then the other factor is (2x+1).

Factor means that we have to split an expression into multiple values and make the power of the variable linear.

For a quadratic equation, there will be 2 factors.

We have the polynomial

2 x² + 3 x + 1

Using middle term splitting, we get that:

= 2 x² + 2 x + x + 1

Taking common factor:

= 2 x ( x + 1) + 1 (x + 1)

= (2 x + 1)( x + 1)

Therefore, we get that if one factor of the polynomial 2 x² + 3 x + 1 is (x+1), then the other factor is (2x+1).

Learn more about polynomials here:

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arsen [322]1 year ago

6 0

Answer:

One factor of the polynomial is (x+1) . which expression represents the other factor, or factors, of the polynomial 2x^2 + 3x+1?

Factors means splitting one value in multiplicative values like if we take an equation like 2x^2 + 3x + 1

Then we can divided these equation in two parts like

2X^2 + 3x +1

= 2x^2 + 2x+x+1

= 2x^2+x+2x+1

=x(2x+1)+1(2x+1)

= (2x+1)(x+1)

So if again we multiply these two factor it will give 2x^2+3x+1 so form here we can say that (2x+1) and (x+1) are the two factors of 2x^2 + 3x+ 1

Kniw more about “Factors” here: brainly.com/question/28315959

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Question: One factor of a polynomial is (x+1) . which expression represents the other factor, or factors, of the polynomial 2x^2 + 3x + 1 ?

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What is the slope of the line that is perpendicular to the given line x-2y=10?

Anuta_ua [19.1K]

Answer: slope = 1/2

Step-by-step explanation:

X-2y=10

-2y=-x-10 subtract x from both sides

2y=x+10 divide by -1

y=<u>1</u> x + 5 Divide by 2

slope = 1/2

6 0

3 years ago

A point $(x, y)$ with integer coordinates is randomly selected such that $0 \le x \le 8$ and $0 \le y \le 4$. what is the probab

ahrayia [7]

Answer:

$\frac{1}{3}$

Step-by-step explanation:

A point (x, y) with integer coordinates is randomly selected such that $0 \le x \le 8 \:and\: $0 \le y \le 4$.$

The possible pairs of (x,y) are:

(0,0),(0,1),(0,2),(0,3),(0,4)

(1,0),(1,1),(1,2),(1,3),(1,4)

(2,0),(2,1),(2,2),(2,3),(2,4)

(3,0),(3,1),(3,2),(3,3),(3,4)

(4,0),(4,1),(4,2),(4,3),(4,4)

(5,0),(5,1),(5,2),(5,3),(5,4)

(6,0),(6,1),(6,2),(6,3),(6,4)

(7,0),(7,1),(7,2),(7,3),(7,4)

(8,0),(8,1),(8,2),(8,3),(8,4)

The Total Possible Outcomes n(S)= 45

The pair (x, y) that satisfies the given condition (say event A: $x + y \le 4$ ) are:

$(0,0),(0,1),(0,2),(0,3),(0,4)\\(1,0),(1,1),(1,2),(1,3)\\(2,0),(2,1),(2,2)\\(3,0),(3,1)\\(4,0)$

n(A)=15

Therefore:

$P(A)=\frac{n(A)}{n(S)} =\frac{15}{45} =\frac{1}{3}$

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=5%20%7Bx%7D%5E3%20-%2020%20%7Bx%7D%5E%7B2%7D%20%3D%200" id="TexFormula1" title="5 {x}^3 - 20 {

adell [148]

$5x^{2} \times (x - 4) = 0 \\ x^{2} \times (x - 4) = 0 \\ {x}^{2} = 0 \: x = 0 \\ x - 4 = 0 \: x = 4$

7 0

3 years ago

Find the volume of the wedge with vertices at points (0,0,0), (1,0,0), (0,1,0), (0,0,1) by integrating the area of cross-section

Angelina_Jolie [31]

Answer:

V = 1/6 cubic units

Step-by-step explanation:

Applying the concept of integrals for volume calculation:

$V = \int\limits^b_a {S(x)} \, dx$ (1)

V = volume of the solid bounded by x = a and x = b

S(x) = cross section area of the solid, perpendicular to the x axis

From the figure we have that S is the area of a triangle that has base Z and height Y

Area of the triangle = $S(x)=\frac{y(x)*z(x)}{2}$ (2)

Calculation of y(x) and z(x)

We apply the equation of the point-slope line (plane xy):

Slope = $m = \frac{y_{2} - y_{1} }{x_{2} - x_{1}}$ (3)

Equation of the line = $y - y_{1} =m(x-x_{1} )$ (4)

Replacing the points (1,0) and (0,1) in (3):

$m=\frac{1-0}{0-1} =-1$

Replacing the point (1,0) and m = -1 in (4):

$y-0=(-1)(x-1)$

y(x) = -x + 1 (Line A-B) (5)

We apply the equation of the point-slope line (plane xz):

Slope = $m = \frac{z_{2} - z_{1} }{x_{2} - x_{1}}$ (6)

Equation of the line = $z - z_{1} =m(x-x_{1} )$ (7)

Replacing the points (1,0) and (0,1) in (6):

$m=\frac{1-0}{0-1} =-1$

Replacing the point (1,0) and m = -1 in (7):

$z-0=(-1)(x-1)$

z(x) = -x + 1 (Line A-C) (8)

Replacing (5) and (8) in (2)

$S(x) = \frac{(-x + 1) * (-x + 1)}{2} =\frac{(-x + 1)^{2} }{2}$ (9)

Replacing (9) in (1) and knowing that a = 0 and b = 1:

$V = \int\limits^1_0 {\frac{(-x + 1)^{2} }{2}} \, dx = \int\limits^1_0 {\frac{x^{2}-2x+1 }{2}} \, dx$

$V =\frac{1}{2} (\frac{x^{3} }{3} -2\frac{x^{2} }{2} +x)$ evaluated from x=0 to x=1

$V= \frac{1}{2} (\frac{1}{3} -1 +1) = \frac{1}{6}$

3 0

3 years ago

Help! I need the answer for this. 5x^2-16x+13=10

tatiyna

Answer:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

Exact Form:

x=1/5,3

Decimal Form:

x=0.2,3

4 0

2 years ago