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ollegr [7]
1 year ago
9

Financial account and managerial accounting.

Mathematics
1 answer:
Helga [31]1 year ago
4 0

1. The differences between managerial accounting and financial accounting are:

  • Internal use vs. external use
  • Management Estimates vs. Adherence to GAAP framework.

2. The types of reports that management accounting produces, which enable managers and internal stakeholders to make future financial decisions for the business, are:

  • Cost reports
  • Performance reports
  • Budget  variance reports
  • Account receivable aging reports.

3. The types of reports that financial accounting produces, which enable external and internal stakeholders to make economic and investment decisions are:

  • Income statement
  • Cash flow statement
  • Balance sheet.

Thus, financial accounting reports facilitate the board of directors, stockholders, potential investors, creditors, financial institutions, and other external stakeholders to make long-term economic decisions, and management accounting reports enable management to make short-term decisions.

Learn more about the differences between financial accounting and management accounting at brainly.com/question/13592085

#SPJ1

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Solve for x. Round your answer to the nearest tenth (0.1)
Marizza181 [45]

Answer:

x\approx 7.0

Step-by-step explanation:

Since we are given a right triangle, we can use right trigonometric ratios.

<em>x</em> is the opposite side to our angle. 10 is the adjacent side to it. Thus, we can use the tangent ratio:

\displaystyle \tan(\theta^\circ)=\frac{\text{opposite}}{\text{adjacent}}

Substitute:

\displaystyle \tan(35^\circ)=\frac{x}{10}

Solve for <em>x:</em>

<em />x=10\tan(35^\circ)<em />

Use a calculator:

x=7.0020...\approx 7.0

7 0
2 years ago
Read 2 more answers
please help i rly need it my math teacher gave me over 30 assignments and a project that are all due tomorrow today and i want t
Sedaia [141]

Answer:

x= -14

Step-by-step explanation:

-14 subtracted by 2 is -16, since its absolute it means its positive, meaning its 16 greater than 14, I may be wrong so just to let you know. Depends on how the teacher wants it to be.

8 0
2 years ago
Select all expressions that are equivalent to 5n-30
mamaluj [8]

Answer: everything EXCEPT 5(n-30)

Step-by-step explanation:

8 0
2 years ago
The figures shown are similar. What is the scale factor? Two similar pentagons, one pentagon with base 9 and one pentagon with b
Oksi-84 [34.3K]
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7 0
3 years ago
Read 2 more answers
Construct a​ 99% confidence interval for the population​ mean, mu. Assume the population has a normal distribution. A group of 1
Zarrin [17]

Answer:

99% confidence interval for the population​ mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population​ mean is given by;

         P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean age of selected students = 22.4 years

             s = sample standard deviation = 3.8 years

             n = sample of students = 19

             \mu = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population​ mean, \mu is ;

P(-2.878 < t_1_8 < 2.878) = 0.99  {As the critical value of t at 18 degree of

                                                freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 2.878) = 0.99

P( -2.878 \times {\frac{s}{\sqrt{n} } } < {\bar X - \mu} < 2.878 \times {\frac{s}{\sqrt{n} } } ) = 0.99

P( \bar X -2.878 \times {\frac{s}{\sqrt{n} } < \mu < \bar X +2.878 \times {\frac{s}{\sqrt{n} } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X -2.878 \times {\frac{s}{\sqrt{n} } , \bar X +2.878 \times {\frac{s}{\sqrt{n} } ]

                                                 = [ 22.4 -2.878 \times {\frac{3.8}{\sqrt{19} } , 22.4 +2.878 \times {\frac{3.8}{\sqrt{19} } ]

                                                 = [19.891 , 24.909]

Therefore, 99% confidence interval for the population​ mean is [19.891 , 24.909].

6 0
3 years ago
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