All categories

2 years ago

I need to know how to solve for the value of x

Mathematics

1 answer:

dimulka [17.4K]2 years ago

8 0

Hey Katie

4^2x+3 = 1
We need to solve for x

log(4^2x+3) = log (1)
Now take log of
(2x +3) * log (4) = log (1)
2x + 3 = log(1)/log(4)
2x + 3 = 0
2x = 0 - 3
2x = -3
x = -3/2

I hope that's help !

You might be interested in

I really need help please (links will be reported)

mrs_skeptik [129]

Answer: all the ones that do not have a negative sign in front easy.

7 0

2 years ago

Use simpson's rule with n = 10 to approximate the area of the surface obtained by rotating the curve about the x-axis. compare y

Lubov Fominskaja [6]

y = ln x , 1 <= x <= 3, about x axis and n = 10, dy/dx = 1/ x

S = (b a) ∫ 2π y √( 1 + (dy/dx) ^2) dx

so our f(x) is 2π y √( 1 + (dy/dx) ^2)

(b - a) / n = / 3 = (3-1) / 30 = 1/15

x0 = 1 , x1 = 1.2, x2 = 1.4, x3 = 1.6 ....... x(10) = 3

So we have , using Simpsons rule:-

S10 = (1/15) ( f(x0) + 4 f(x1) + 2 f)x2) +.... + f(x10) )

= (1/15) f(1) + f(3) + 4(f(1.2) + f(1.6) + f(2) + f(2.4) + f(2.8)) + 2(f(1.4) + f(1.8) + f(2.2) + f(2.6) )

( Note f(1) = 2 * π * ln 1 * √(1 + (1/1)^2) = 0 and f(3) = 2π ln3√(1+(1/3^2) = 7,276)

so we have S(10)

= 1/15 ( 0 + 7.2761738 + 4(1.4911851 +

5 0

3 years ago

AB ≅ BC and AD ≅ CD What additional information would make it immediately possible to prove that triangles AXB and CXB are congr

kobusy [5.1K]

It is given that, B ≅ BC and AD ≅ CD

We need BD perpendicular to AC, then only we can say triangles AXB and CXB are congruent using the HL theorem.

If BD perpendicular to AC, means that AB and CB are the hypotenuse of triangles AXB and CXB respectively.

from the given information ABCD is a square

If BD and AC bisect each other then AX = CX

Then only we can immediately possible to prove that triangles AXD and CXD are congruent by SSS congruence theorem

5 0

3 years ago

Read 2 more answers

Does second-hand smoke increase the risk of a low birthweight? A baby is considered have low birthweight if he/she weighs less t

marishachu [46]

Answer:

Option 2) Null hypothesis: p = 0.078 , Alternate hypothesis: p > 0.078

Step-by-step explanation:

We are given the following in the question:

According to the National Center of Health Statistics, about 7.8% of all babies born in the U.S. are categorized as low birth weight.

Sample size, n = 1200

p = 7.8% = 0.078

We have to carry a hypothesis test whether national percentage is higher than 7.8% or not.

Thus, we can design the null and the alternate hypothesis

$H_{0}: p = 0.078\H_A: p > 0.078$

Thus, the correct answer is:

Option 2) Null hypothesis: p = 0.078 , Alternate hypothesis: p > 0.078

5 0

2 years ago

Verify csc^2t-cos t sect= cot^2 t

Ymorist [56]

Rewriting the left hand side,

csc²t - cost sec t

= (1/sin²t)-(cost)(1/cost)

= 1/sin²t - 1

= 1/sin²t - sin²t/sin²t

= (1-sin²t)/sin²t

= cos²t/sin²t

= cot²t

7 0

2 years ago

Read 2 more answers