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tamaranim1 [39]
3 years ago
13

I need to know how to solve for the value of x

Mathematics
1 answer:
dimulka [17.4K]3 years ago
8 0
Hey Katie

4^2x+3 = 1
We need to solve for x

log(4^2x+3) = log (1)
Now take log of
(2x +3) * log (4) = log (1)
2x + 3 = log(1)/log(4)
2x + 3 = 0
2x = 0 - 3
2x = -3
x = -3/2


I hope that's help ! 

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