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malfutka [58]
3 years ago
9

numerele a, b si c sunt direct proportionale cu 2, 3 si 5. Daca media aritmetica a celor trei numere este egala cu 100, determin

ati numerele a, b si c
Mathematics
1 answer:
Fynjy0 [20]3 years ago
3 0

Answer:

a = 60

b = 90

c = 150

Step-by-step explanation:

Numerele a, b și c sunt direct proporționale cu 2, 3 și 5.

Unde k este constantă de proporționalitate

a ∝ 2

a = 2k

b ∝ 3

b = 3k

c ∝ 5

c = 5k

Dacă media aritmetică a celor trei numere este egală cu 100, determinați numerele a, b și c

= 2k + 3k + 5k / 3 = 100

= 10k / 3 = 100

Cross Multiply

= 10k = 3 × 100

= 10k = 300

Împărțiți ambele părți la 10

k = 300/10

k = 30

Pentru numărul a

a = 2k

a = 2 × 30

a = 60

Pentru numărul b

b = 3k

b = 3 × 30

b = 90

Pentru numărul c

c = 5k

c = 5 × 30

c = 150

Prin urmare, a = 60, b = 90, c = 150

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The complete question is:

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