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2 years ago

How much interest will you earn in 1 year on a $8000 deposit at 2.5%? NEED HELP!!

Mathematics

2 answers:

77julia77 [94]2 years ago

3 0

Yes I would like to get to solve the problem

charle [14.2K]2 years ago

3 0

Answer:

2400

Step-by-step explanation:

8000×2.5%=200×12=2400

this is if it's monthly and there are 12 months in a year

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What is the value of 3b when b = 18?

lubasha [3.4K]

Answer:

Step-by-step explanation:

to evaluate substitute b = 18 into 3b

3b = 3 × 18 = 54

4 0

3 years ago

Read 2 more answers

Order from least to greatest 1.25, 1.52, 1.02, 1.50

marusya05 [52]

Answer:

1.02 1.25 1.50 1.52.

Step-by-step explanation:

|•-•|

7 0

2 years ago

Read 2 more answers

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago

6x+4y=42 -3x+3y=-6 by elimination

creativ13 [48]

Answer:

x=5, y=2

Step-by-step explanation:

To solve this system, we need to find x and y. First, let's find x. In the first equation (6x+4y=42), subtract 4y on both sides to isolate 6x. This will result in 6x=42-4y. Divide by 6 on both sides to isolate x and get x=7- $\frac{2}{3}$ y. Now we know what x equals. Go to the second equation ad plug this into it. So instead of -3x+3y=-6, you'll have -3(7- $\frac{2}{3}$ y)+3y=-6. Use the distributive property to get -21+2y+3y=-6. Add 2y and 3y to get -21+5y=-6. Add 21 to both sides to isolate 5y and get 5y=15. Divide by 5 on both sides to isolate y and get y=3. Now that we know that y=3, we can plug this back into the equation that was bolded above so that we can find x, so we'll have x=7- $\frac{2}{3}$ (3) since y=3, and we'll get x=7- $\frac{6}{3}$ , or x=7-2, or x=5.