Question

During an adiabatic compression a volume of an air decrease to 1/4 th its original size calculate its final pressure if its original pressure was 1 atm

Answer 1

The final pressure is 6.96 atm.

We know that in an adiabatic process,

$p_{1} V_{1} ^{gamma}$ = $p_{2} V_{2} ^{gamma}$

where,

p = Pressure

V = Volume

Gamma = Isentropic expansion factor

Given that,

$p_{1}$ = 1 atm

γ = 1.4 ( Assuming the air as an ideal gas )

$V_{2}$ = $V_{1}$ / 4

$V_{1}$ / $V_{2}$  = 4

$p_{1} V_{1} ^{1.4}$ = $p_{2} V_{2} ^{1.4}$

$p_{2}$ = 1 * $( 4 )^{1.4}$ = 6.96 atm

An adiabatic process is a thermodynamic process without the involvement of heat. Usually it takes place in an insulated box.

Therefore, the final pressure is 6.96 atm

To know more about adiabatic process

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