All categories

2 years ago

Someone help me please

Physics

1 answer:

Maru [420]2 years ago

8 0

H I and u your weclome

You might be interested in

How many pounds must a sandbag weigh to test if a safety net can absorb the proper amount of force

inessss [21]

I believe its 400lbs

3 0

3 years ago

Read 2 more answers

What is needed to make alternative energy sources widely accepted?

svp [43]

i think what is needed is for people to see that alt. energy sources are very useful and inexpensive.

4 0

4 years ago

I need help with all of these questions

Sedbober [7]

Answer:

This was my best estimation of the answers

7 0

3 years ago

If the sphere on the left is moved closer to the central cylinder and placed at a distance R/2 from the axis of rotation, what i

Alexxx [7]

Answer:

$\alpha= \frac{2rF}{3mR}$

Explanation:

The torque reqired to rotate the above masses rod system

$\tau = rF= I\alpha$ ...............(1)

Total moment of inertia of masses and rod is

$I=2m\left ( \frac{R}{2} \right )^2+mR^{2}$

= $\frac{3}{2} mR^{2}$

now Substitute I= $\frac{3}{2} mR^{2}$ in the (1) we get

$rF= \frac{3}{2}mR^{2}\alpha$

rearranging for alpha we get

$\alpha= \frac{2rF}{3mR}$

hence the acceleration is

$\alpha= \frac{2rF}{3mR}$

7 0

4 years ago

Currents in dc transmission lines can be 100 A or more. Some people have expressed concern that the electromagnetic fields (EMFs

S_A_V [24]

Explanation:

This problem can be solved by using the equation

B = (μ0*I)/(2π*r) ( 1 )

where μ0 is the magnetic permeability, I is the current in the wire and r is the distance to the wire, where the magnetic field B is calculated. The equation (1) says that a current in a wire produce a magnetic field in a distance r from the wire.

Part A

Taking into account that μ0 = $4\pi *10^{-7} \frac{N}{A^{2}}$

By replacing in the equation ( 1 ) we have:

$B = \frac{4\pi *10^{-7}N/A^{2}(180A)}{2\pi (8m)} = 4.5*10^{-6} T$

Part B

In tis case is only necessary to calculate B/Be (Be is the magnetic field of the earth), but taking into account that tha magnetic field of the earth must be in teslas.

1 gauss = 10^(-4) T

0.50 gauss = 0.50*(10^(-4)) T = 5*10^(-5) T

Hence, the proportion between B and Be:

$\frac{B}{B_{e}} = \frac{4.5*10^{-6}}{5*10^{-5}} = 0.09 = 9%$

Thus, it is only 9% of the magnetic field of the earth.

8 0

4 years ago

Read 2 more answers