Someone help me please

Two cars collide at an intersection. One car has a mass of 1600 kg and is

pickupchik [31]

The combined momentum is 4000 kg m/s south

Explanation:

The total combined momentum of the two cars is given by the vector addition of the momenta of the two cars.

For this problem, we choose north as positive direction and south as negative direction.

The momentum of the first car travelling north is given by:

$p_1 = m_1 v_1$

where

$m_1 = 1600 kg$ is the mass of the car

$v_1 = +8 m/s$ is its velocity

Substituting,

$p_1 = (1600)(8)=+12800 kg m/s$

The momentum of the second car travelling south is given by:

$p_2 = m_2 v_2$

where

$m_2 = 1400 kg$ is the mass of the car

$v_2= -12 m/s$ is its velocity (negative because the car travels south)

Substituting,

$p_2 = (1400)(-12)=-16800 kg m/s$

And therefore, the combined momentum is

$p=p_1 + p_2 = +12800 + (-16800)=-4000 kg m/s$

where the negative sign means the direction of the total momentum is south.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

4 0

3 years ago

In attempting to pass the puck to a teammate, a hockey player gives it an initial speed of 2.8 m/s. However, this speed is inade

erastova [34]

Answer:

3.95979 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v^2-u^2=2as\\\Rightarrow as=\frac{v^2-u^2}{2}\\\Rightarrow as=\frac{0^2-2.8^2}{2}\\\Rightarrow as=-3.92$

Here $s=\frac{1}{2}s$

$\\\Rightarrow as=-7.84\ m/s^2$

$v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -7.84}\\\Rightarrow u=3.95979\ m/s$

Initial velocity of the puck should be 3.95979 m/s

8 0

3 years ago

Compare blue and red light from the visible spectrum. which has: the longer wavelength? the greater frequency? the greater energ

Hitman42 [59]

1) By looking at the table of the visible spectrum, we see that blue light has a wavelength in the range [450-490 nm], while red light has wavelength in the range [620-750 nm]. Therefore, red light has longer wavelength than blue light.

2) The frequency f of an electromagnetic wave is related to its wavelength $\lambda$ by the formula
$f= \frac{c}{\lambda}$
where c is the speed of light. We see that the frequency is inversely proportional to the wavelength, so the shorter the wavelength, the greater the frequency. In this case, blue light has shorter wavelength than red light, so blue light has greater frequency than red light.

3) The energy of the photons of an electromagnetic wave is given by
$E=hf$
where h is the Planck constant and f is the frequency. We see that the energy is directly proportional to the frequency, so the greater the frequency, the greater the energy. In this problem, blue light has greater frequency than red light, so blue light has also greater energy than red light.

6 0

3 years ago

What is the speed of a bobsled whose distance-time graph indicates that it traveled 123m in 28s?

Irina18 [472]

4.39 seconds per meter

6 0

3 years ago

Why does a mountain of uranium not explode as a bomb?

djyliett [7]

Answer:

“A mountain of uranium” is an indefinable amount of uranium. If it means uranium ore as found in nature, then the concentration of uranium is orders of magnitude too low for any type of reaction.

Explanation:

smarty

7 0

3 years ago

Read 2 more answers