Answer:
Explanation:
Young's modulus of elasticity Y = stress / strain
stress = force / cross sectional area
= weight of 15 kg / π r²
= 15 x 9.8 / 3.14 x ( .025 x 10⁻² )²
stress = 74.9 x 10⁷ N / m²
strain = Δ L / L , Δ L is change in length and L is original length
Putting the values
strain = .0168 / 2.7 =.006222
Young's modulus of elasticity Y = 74.9 x 10⁷ / .006222
= 120.88 x 10⁹ N / m² .
Answer : Option C) copy the movements performed during the activity.
Explanation : Arm circles are an effective dynamic stretch for swimmers because they copy the movements performed during the activity.
During swimming when the arm circles are performed it stretches the triceps brachii, loosens the shoulder blade and stretches the side muscles.
Often many people are observed to perform this arm circles stretch without bringing the elbow behind the head, but especially for swimmers, this increases the stretching length and reduces stress while swimming.
Answer:
The velocity of the proton is 
Explanation:
The momentum of a particle is defined as the product of its mass by its velocity and we can calculate it using the following formula:
p=m*v Equation (1)
Where:
p: Is the momentum in kg*m/s
m: Is mass of the particle in kg
v: Is the velocity of the particle in m/s
Data known:
m= 1,6726 × 10^–27 kg : mass of the proton
p= 4.96 X 10^-19 kg.m/s.
We replace this data in the Equation (1):
Answer: The velocity of the proton is
Answer:
a.) 2.66 seconds for 79.2 km/h and 1.82 seconds for 47.8 km/h
b.)-4.13 m/s2 for 79.2 km/h and -3.63 m/s2 for 47.8 km/h
Explanation:
Now for (a)
time = velocity/distance
for velocity = 79.2 km/h and distance 0.0586 km
t = (0.0586/79.2)*3600
t = 2.66 seconds (Please note that multiplication with 3600 is to convert hours into seconds)
for velocity 47.8 km/h and distance 0.0242 km
t = (0.0242/47.8)*3600
t = 1.82 seconds
Now for (b)
2as = vf2-vi2
so,
2a(58.6) = -(79.2*1000/3600)^2 (Please note that multiplication and division with 1000 and 3600 respectively is to convert speed unit from km/h to m/s)
a = -4.13 m/s2 for 58.6 m
and
2a(24.2) = -(47.8*1000/3600)^2
a = -3.63 m/s2 for 24.2 m.
Please note that "-" sign express the deceleration.
As you inhale, your ribs move up and out decreasing the internal pressure and increasing the volume of the lungs forcing air into the lungs from an area of externally high pressure in comparison to the low internal pressure.
