Given :
h= 1.57 m, x = 3.17 m, and vb = 3.03 m/s .
To Find :
The upward velocity of cylinder .
Solution :
Component of along string .
Now ,
Now , from the figure :
Putting all given values in above equation :
Therefore , value of is 6.76 m/s .
Hence , this is the required solution .
Answer:
Explanation:
frequency of vibration
n = 40 / 22.3 per second.
= 1.794 per second
velocity of wave v = 369 / 13.5 cm / s
= 27.33 cm / s
wavelength = velocity / frequency
= 27.33 / 1.794
= 15.23 cm
Answer:
i only wrote this for points
Explanation:
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4) The lost value is $4500.
5) The values in a $ are Dependent variable in the graph.
6) Time(year) is inversely proportional to the values in $.
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Explanation:
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4) To calculate a loss between 2005 and 2006 we will find the value on the y-axis for 2005(which is on the x-axis) from the graph and subtract it by the value on the y-axis for 2006(which is on the x-axis) from the graph.
loss between 2005 and 2006 = $14500-$10000
= $4500
Percentage of loss is 31.03%
5) A dependent variable is a variable being tried and estimated in a logical test. The dependent variable in the graph is the value of the car that is given in the Dollar($). We can see that by the increase of the time there is an effect on the value of the car and the dependent variables are taken on the y-axis.
6) From the graph, It is shown that with an increase in time(year) the value of Sarah's car decreases and with the decrease in time its value increases. So it is clear that time is inversely proportional to the value of the car. By every passing year, the value of the car decreases.
Answer:
v = 0
Explanation:
This problem can be solved by taking into account:
- The equation for the calculation of the period in a spring-masss system
( 1 )
- The equation for the velocity of a simple harmonic motion
( 2 )
where m is the mass of the block, k is the spring constant, A is the amplitude (in this case A = 14 cm) and v is the velocity of the block
Hence
and by reeplacing it in ( 2 ):
In this case for 0.9 s the velocity is zero, that is, the block is in a position with the max displacement from the equilibrium.