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IgorC [24]
3 years ago
6

3 sentences or more..........

Physics
2 answers:
mylen [45]3 years ago
6 0

Answer:

me no speak the english

Explanation:

rjkz [21]3 years ago
5 0

hi...............dhfhrhiwbwbwbdjdnbs d.d.d.d.d.smsjsns.ddjsns.d.dmdjdjdjd

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What is the average power developed by a motor as it lifts a 400.-kilogram mass at constant speed through a vertical distance of
Tomtit [17]

Answer:

The average power developed by a motor is 4905 Watts.

Explanation:

The average power is given by:

P = \frac{W}{t}

Where:

W: is the work

t: is the time = 8.0 s

First, let's find the work:

W = F*d

Where:

F: is the force

d: is the displacement = 10.0 m

The force is in the vertical motion, and since the movement of the mass is at constant speed the force is:

F = mg = 400 kg*9.81 m/s^{2} = 3924 N

Hence, the average power is:

P = \frac{F*d}{t} = \frac{3924 N*10.0 m}{8.0 s} = 4905 J/s = 4905 W                    

Therefore, the average power developed by a motor is 4905 Watts.

I hope it helps you!                  

3 0
3 years ago
Gravity causes___ objects to accelerate
kolbaska11 [484]
Gravity causes falling objects to accelerate.
4 0
4 years ago
Read 2 more answers
what is the driver doing when they are holding their foot over top of the accelerator but not touching it?
notka56 [123]
Hovering their foot over the gas petal.
8 0
2 years ago
Which of the following represents an upright image? <br> A. -do<br> B. +m<br> C. -m<br> D. +do
Tom [10]

Answer:

B. +m

Explanation:

The magnification of an image is defined as the ratio between the size of the image and of the object:

m = \frac{y'}{y}

where we have

y' = size of the image

y = size of the object

There are two possible situations:

- When m is positive, y' has same sign as y: this means that the image image is upright

- When m is negative, y' has opposite sign to y: this means that the image is upside down

Therefore, the correct option representing an upright image is

B. +m

5 0
3 years ago
A point charge of -4.28 pC is fixed on the y-axis, 2.79 mm from the origin. What is the electric field produced by this charge a
makkiz [27]

Answer:

E = (-3.61^i+1.02^j) N/C

magnitude E = 3.75N/C

Explanation:

In order to calculate the electric field at the point P, you use the following formula, which takes into account the components of the electric field vector:

\vec{E}=-k\frac{q}{r^2}cos\theta\ \hat{i}+k\frac{q}{r^2}sin\theta\ \hat{j}\\\\\vec{E}=k\frac{q^2}{r}[-cos\theta\ \hat{i}+sin\theta\ \hat{j}]              (1)

Where the minus sign means that the electric field point to the charge.

k: Coulomb's constant = 8.98*10^9Nm^2/C^2

q = -4.28 pC = -4.28*10^-12C

r: distance to the charge from the point P

The point P is at the point (0,9.83mm)

θ: angle between the electric field vector and the x-axis

The angle is calculated as follow:

\theta=tan^{-1}(\frac{2.79mm}{9.83mm})=74.15\°

The distance r is:

r=\sqrt{(2.79mm)^2+(9.83mm)^2}=10.21mm=10.21*10^{-3}m

You replace the values of all parameters in the equation (1):

\vec{E}=(8.98*10^9Nm^2/C^2)\frac{4.28*10^{-12}C}{(10.21*10^{-3}m)}[-cos(15.84\°)\hat{i}+sin(15.84\°)\hat{j}]\\\\\vec{E}=(-3.61\hat{i}+1.02\hat{j})\frac{N}{C}\\\\|\vec{E}|=\sqrt{(3.61)^2+(1.02)^2}\frac{N}{C}=3.75\frac{N}{C}

The electric field is E = (-3.61^i+1.02^j) N/C with a a magnitude of 3.75N/C

8 0
3 years ago
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