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katen-ka-za [31]
3 years ago
11

Humans have existed for about 106 years, whereas the universe is about 1010 years old. If the age of the universe is defined as

1 "universe day," where a universe day consists of "universe seconds" as a normal day consists of normal seconds, how many universe seconds have humans existed?
Physics
1 answer:
son4ous [18]3 years ago
8 0

Answer:

8.64 seconds

Explanation:

According to the question

10^{10}\ years=1\ day

1\ year=\dfrac{1}{10^{10}}\ day

Humans have lived for 10^6 years

In one universe day

10^6\ years=10^6\times \dfrac{1}{10^{10}}=10^{-4}\ day

In seconds

10^{-4}\times 24\times 60\times 60=8.64\ seconds

In one universe day humans have lived for 8.64 seconds

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Answer:1.7\times 10

Explanation:

Given

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time interval t=2.5 s

Impulse is given by =Force \times time\ interval\ for\ applied\ force

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For two significant Figure

Impulse=1.7\times 10

                       

7 0
3 years ago
A 40.0-mH inductor is connected to a North American electrical outlet (ΔVrms = 120 V, f = 60.0 Hz). Assuming the energy stored i
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Explanation:

It is given that,

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The current flowing through the inductor is given by :

I_t=\dfrac{V_o}{X_L}\ (sin\ \omega t-\dfrac{\pi}{2})

I_t=\dfrac{\sqrt{2} V_{rms}}{X_L}\ (sin\ \omega t-\dfrac{\pi}{2})

I_t=\dfrac{120\sqrt{2}}{2\pi f L}\ sin(2\pi f t-\dfrac{\pi}{2})

I_t=\dfrac{120\sqrt{2}}{2\pi\times 60\times 40\times 10^{-3}}\ sin(2\pi \times 60\times \dfrac{1}{185})-\dfrac{\pi}{2})    

I_t=\dfrac{120\sqrt2}{15.07}\ sin(2\pi \times 60\times \dfrac{1}{185}-\dfrac{\pi}{2})

I = 0.091 A

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U=\dfrac{1}{2}\times 40\times 10^{-3}\times (0.091)^2

U = 0.000165 Joules

Hence, this is the required solution.

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Answer:

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