Question

An emf of 0.50 v is induced across a coil when the current through it changes uniformly from 0.55 to 0.95 a in 0.40 s. what is the self-inductance of the coil (in h)?

Answer 1

The correct answer is 0.67 h

The coil's induced emf is specified as e=0. 50 v.

i i = 0.55 A is the initial value of the current flow.

I f = 0.95 A is the total amount of current flowing.

The shift in current occurs in a period of time when dt = 0.40 s.

The self-inductance is determined as follows:

The current change rate is represented here by dI/dt.

Step 2 After entering the values,

As a result, the self-inductance is 0.67 H.

The definition of self inductance is the induction of a voltage in a wire that carries current when the current in the wire is changing. When there is self-inductance, a circuit's own changing current creates a magnetic field that causes a voltage to be induced.

Learn more about Self inductance here :-

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