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3 years ago

3. Why is a train so hard to stop even when it is going slowly?

Physics

2 answers:

Nesterboy [21]3 years ago

6 0

Answer:

For trains the wheels and the rail are both steel, and the steel-steel friction coefficient is around 0.25. So the stopping time and distance will, at best, be three to four times greater than a car.

Explanation:

Nitella [24]3 years ago

5 0

Answer: them things weigh tons and tons. like hundreds of tons. whenever the train is even slightly moving, the force is still so great that it makes it very difficult to stop.

Explanation: my brain knows

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tankabanditka [31]

Answer:

If the Lego building is shaken side to side, it will withstand up to 60 seconds because front to back will cause the top of the building to collapse.

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2 years ago

A coil 4.20 cm radius, containing 500 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×1

erma4kov [3.2K]

Explanation:

Given that,

Radius of the coil, r = 4.2 cm

Number of turns in the coil, N = 500

The magnetic field as a function of time is given by :

$B=1.2\times 10^{-2}t+2.6\times 10^{-5}t^4$

Resistance of the coil, R = 640 ohms

We need to find the magnitude of induced emf in the coil as a function of time. It is given by :

$\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{-d(NBA)}{dt}\\\\\epsilon=N\pi r^2\dfrac{-dB}{dt}\\\\\epsilon=N\pi r^2\times \dfrac{-d(1.2\times 10^{-2}t+2.6\times 10^{-5}t^4)}{dt}\\\\\epsilon=N\pi r^2\times (1.2\times 10^{-2}+10.4\times 10^{-5}t^3)\\\\\epsilon=500\pi \times (4.2\times 10^{-2})^2\times (1.2\times 10^{-2}+10.4\times 10^{-5}t^3)\\\\\epsilon=2.77(1.2\times 10^{-2}+10.4\times 10^{-5}t^3)\ V$

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3 years ago

Read 2 more answers

What was the hikers average velocity during part D of the hikes?

pychu [463]

Velocity = displacement / time
v = 6 / 3/4
v = 6*4/3
v = 24/3
v = 8 m/s toward north

In short, Your Answer would be 8 m/s north

Hope this helps!

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4 years ago

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The force that acts on all objects, all the time on Earth is gravitational force.

The force that surface exert on an object perpendicularly is normal reaction.

<h3>What force acts on all objects, all the time on Earth?</h3>

Force due to gravity is gravitational pull on objects due to its position on earth's surface.

The force due to gravity on object's is calculated by applying Newton's second law of motion as follows;

F = mg

where;

m is the mass of the object
g is acceleration due to gravity

The force that surface exert on an object perpendicularly is normal reaction.

Thus, the force that acts on all objects, all the time on Earth is gravitational force.

Learn more about force of gravity here: brainly.com/question/2537310

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