Irregular heating of the air can produce thermals which are ________.
1 answer:
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Answer:
capacitance = 2.242 × F
charge = 1.345 × C
electric field = 600 V/m
work done = 8.07 × J
Explanation:
given data
battery c = 12 V
diameter = 10 in
distance d = 2 cm = 2× m
to find out
capacitance , charge on plate, electric field and work done
solution
we know radius is diameter / 2
so radius r = 10 / 2 = 5 in = 0.127 m
and capacitance formula that is
capacitance = A∈/d
put here all value
capacitance = πr² ∈/d
capacitance = π(0.127)² ×8.85 × /2×
capacitance = 2.242 × F
and
charge on plate is express as
charge = capacitance × c
we know here 2 plate so on 1 plate c is 6
charge = 2.242 × × 6
charge = 1.345 × C
and
electric field is express as
electric field = c / d
electric field = 12 / 2×
electric field = 600 V/m
and
work done is express as
work done = 1/2 × charge × C
put here value
work done = 1/2 × (1.345 × ) (12)
work done = 8.07 × J