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sergejj [24]
1 year ago
15

Suppose you fill two rubber balloons with air, suspend both of them from the same point, and let them hang down on strings of eq

ual length. You then rub each with wool or on your hair so that the balloons hang apart with a noticeable separation between them. Make order-of-magnitude estimates of (c) the field each creates at the center of the other
Physics
1 answer:
Sidana [21]1 year ago
7 0

The field each creates at the center of the other is 1.7×10^4N/C.

Consider two balloons of diameter 0.200m each with mass 1.00g hanging apart with 0.0500m separation on the ends of string making angles of 10.0° with the vertical

E = ke q /r^2

= [(8.99×10^9N⋅m^2C^2)(1.2×10^−7C)] / (0.25m)^2

= 1.7×10^4N/C

Gauss Law states that the total electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux in an area is defined as the electric field multiplied by the area of the surface projected in a plane and perpendicular to the field.

Learn more about electric flux here:

brainly.com/question/14893386

#SPJ4

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What do the plastic jars of the air capacitor represent in an electrical capacitor? The parallel conducting plates The source of
miss Akunina [59]

The plastic jars of the air capacitor represent the parallel conducting plates.

<h3>What is Air capacitor?</h3>

Air capacitor is a type of capacitor that uses air as its dielectric. The simplest air capacitors will contain two conductive plates separated by an air gap.

This capacitor stores and releases electricity in the circuit using;

  • air as the electrical source,
  • balloon as the insulator and
  • the plastic jar as the parallel conducting plates.

Thus, the plastic jars of the air capacitor represent the parallel conducting plates.

Learn more about air capacitor here: brainly.com/question/15755974

3 0
2 years ago
A lead ball has a mass of 55.0 grams and a density of 11.4 g/cm3. what is the volume of the ball?
lesantik [10]
Density=mass/volume therefore volume=mass/density; 55g/11.4g/cm^3= 4.82cm^3
6 0
3 years ago
Read 2 more answers
A black, totally absorbing piece of cardboard of area a = 2.1 cm2 intercepts light with an intensity of 8.8 w/m2 from a camera s
PolarNik [594]

Answer:

The value of radiation pressure is 2.933 \times 10^{-8} Pa

Explanation:

Given:

Intensity I = 8.8 \frac{W}{m^{2} }

Area of piece A = 2.1 \times 10^{-4} m^{2}

From the formula of radiation pressure in terms of intensity,

   P = \frac{I}{c}

Where P = radiation pressure, c = speed of light

We know value of speed of light,

 c = 3 \times 10^{8} \frac{m}{s}

Put all values in above equation,

  P = \frac{8.8}{3 \times 10^{8} }

  P = 2.933 \times 10^{-8} Pa

Therefore, the value of radiation pressure is 2.933 \times 10^{-8} Pa

8 0
4 years ago
A garage door opener has a power rating of 350 watts.
Lelechka [254]
We Know, Power = Energy/Time
Substitute the known value. which is P = 350 watt, & T = 30 sec
350 = E/30 
E = 350 * 30
E = 1050 Joules.

So, your answer is 1050 Joules.
Hope this helps! Keep studying! 
6 0
3 years ago
Read 2 more answers
A boat has a propulsion system that consists of a pump that sucks water at the bow and presses it on the stern. All tubes are 5
Phoenix [80]

Answer:

The propulsion force at the moment of departure, is 49 N  

Explanation:

Given;

diameter of tubes = 5 cm = 0.05 m

volumetric flow rate, V = 50 L/s = 0.005 m³/s

density of water, ρ = 1000 Kg /m³

hydraulic / propulsion force, F = ρVg

where;

ρ is the density of the fluid (water)

V is the volumetric flow rate of water

g is acceleration due to gravity

propulsion force, F = ρVg

propulsion force, F = 1000 x 0.005 x 9.8

propulsion force, F = 49 N      

Therefore, the propulsion force at the moment of departure, is 49 N  

7 0
4 years ago
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