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sergejj [24]
1 year ago
15

Suppose you fill two rubber balloons with air, suspend both of them from the same point, and let them hang down on strings of eq

ual length. You then rub each with wool or on your hair so that the balloons hang apart with a noticeable separation between them. Make order-of-magnitude estimates of (c) the field each creates at the center of the other
Physics
1 answer:
Sidana [21]1 year ago
7 0

The field each creates at the center of the other is 1.7×10^4N/C.

Consider two balloons of diameter 0.200m each with mass 1.00g hanging apart with 0.0500m separation on the ends of string making angles of 10.0° with the vertical

E = ke q /r^2

= [(8.99×10^9N⋅m^2C^2)(1.2×10^−7C)] / (0.25m)^2

= 1.7×10^4N/C

Gauss Law states that the total electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux in an area is defined as the electric field multiplied by the area of the surface projected in a plane and perpendicular to the field.

Learn more about electric flux here:

brainly.com/question/14893386

#SPJ4

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Which of the following is not a constellation?
Effectus [21]

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C.Betelgeuse

Explanation:

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g What is the final velocity of a hoop that rolls without slipping down a 6.92 m high hill, starting from rest
liberstina [14]

Answer:

The value is  v  = 8.24 \  m/s

Explanation:

From the question we are told that

  The height of the hill is  h =  6.92 \  m

Generally from the law of energy conservation we have that

   PE =  KE +  RKE

Here  PE is the potential energy of the hoop which is mathematically represented as

       PE =  mgh

 KE is the kinetic energy of the hoop  which is mathematically represented as

     KE =  \frac{1}{2}  * m * v^2

And  

  RKE  is the rotational  kinetic energy which is mathematically represented as

      RKE  =  \frac{1}{2}  * I  *  w^2

Here I  is the moment of inertia of the hoop which is mathematically represented as

           I  =   m *  r^2

and  w  is the angular velocity which is mathematically represented as

          w =  \frac{v}{r}

So

         RKE  =  \frac{1}{2}  * m r^2    *  \frac{v}{r} ^2

=>     RKE  =  \frac{1}{2}  * m r    * v^2

So

     mgh =   \frac{1}{2}  * m * v^2 +   \frac{1}{2}  * m r    * v^2

=>   v  =  \sqrt{gh}

=>   v  =  \sqrt{9.8 *  6.92 }

=>   v  = 8.24 \  m/s

5 0
3 years ago
Two particles each have the same mass but particle #1 has four times the charge of particle #2. Particle #1 is accelerated from
marin [14]

Answer:

 v_2 = 2*v  

Explanation:

Given:

- Mass of both charges = m

- Charge 1 = Q_1

- Speed of particle 1 = v

- Charge 2 = 4*Q_1

- Potential difference p.d = 10 V

Find:

What speed does particle #2 attain?

Solution:

- The force on a charged particle in an electric field is given by:

                                       F = Q*V / r

Where, r is the distance from one end to another.

- The Net force acting on a charge accelerates it according to the Newton's second equation of motion:

                                      F_net = m*a

- Equate the two expressions:

                                      a = Q*V / m*r

- The speed of the particle in an electric field is given by third kinetic equation of motion.

                                      v_f^2 - v_i^2 = 2*a*r

Where, v_f is the final velocity,

            v_i is the initial velocity = 0

                                      v_f^2 - 0 = 2*a*r

Substitute the expression for acceleration in equation of motion:

                                       v_f^2 = 2*(Q*V / m*r)*r

                                       v_f^2 = 2*Q*V / m

                                       v_f = sqrt (2*Q*V / m)

- The velocity of first particle is v:

                                       v = sqrt (20*Q / m)

- The velocity of second particle Q = 4Q

                                       v_2 = sqrt (20*4*Q / m)

                                       v_2 = 2*sqrt (20*Q / m)

                                       v_2 = 2*v  

3 0
3 years ago
Please help :)
Orlov [11]

Answer:

<em>3.5 A</em>

Explanation:

Current [A] =Electrical power [W] ÷ Potential difference [V]

KW TO W = ×1000

hence,

800W÷230V= 3.5A (1 d.p)

8 0
3 years ago
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