thats how it works and thanks for points
Answer:
C.Betelgeuse
Explanation:
It's a star in a costellation
;3
Answer:
The value is 
Explanation:
From the question we are told that
The height of the hill is 
Generally from the law of energy conservation we have that

Here PE is the potential energy of the hoop which is mathematically represented as

KE is the kinetic energy of the hoop which is mathematically represented as
And
RKE is the rotational kinetic energy which is mathematically represented as

Here I is the moment of inertia of the hoop which is mathematically represented as

and w is the angular velocity which is mathematically represented as

So

=> 
So

=> 
=> 
=> 
Answer:
v_2 = 2*v
Explanation:
Given:
- Mass of both charges = m
- Charge 1 = Q_1
- Speed of particle 1 = v
- Charge 2 = 4*Q_1
- Potential difference p.d = 10 V
Find:
What speed does particle #2 attain?
Solution:
- The force on a charged particle in an electric field is given by:
F = Q*V / r
Where, r is the distance from one end to another.
- The Net force acting on a charge accelerates it according to the Newton's second equation of motion:
F_net = m*a
- Equate the two expressions:
a = Q*V / m*r
- The speed of the particle in an electric field is given by third kinetic equation of motion.
v_f^2 - v_i^2 = 2*a*r
Where, v_f is the final velocity,
v_i is the initial velocity = 0
v_f^2 - 0 = 2*a*r
Substitute the expression for acceleration in equation of motion:
v_f^2 = 2*(Q*V / m*r)*r
v_f^2 = 2*Q*V / m
v_f = sqrt (2*Q*V / m)
- The velocity of first particle is v:
v = sqrt (20*Q / m)
- The velocity of second particle Q = 4Q
v_2 = sqrt (20*4*Q / m)
v_2 = 2*sqrt (20*Q / m)
v_2 = 2*v
Answer:
<em>3.5 A</em>
Explanation:
Current [A] =Electrical power [W] ÷ Potential difference [V]
KW TO W = ×1000
hence,
800W÷230V= 3.5A (1 d.p)