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GaryK [48]
3 years ago
13

A sonar pulse is sent to the ocean bottom at 25°C, and it takes 1.20 s for the echo to come back. How deep is the bottom?

Physics
1 answer:
Assoli18 [71]3 years ago
4 0
There are several information's of immense importance already given in the question. 
Velocity of sound = 1560 m/s
Time taken for the echo to reach surface = 1.20 second
We already know
Distance = Velocity * Time
               = 1560 * 1.20 meter
               = 1872 meter
So the total distance that the sound travels going down and up = 1872 meter
Then
The depth of the bottom = 1872/2 meter
                                       = 936 meter
                                       = 0.92 km
So the correct option is the second option.
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A massless spring with spring constant 16.4 N/m hangs vertically. A body of mass 0.193 kg is attached to its free end and then r
svet-max [94.6K]

Answer:

(A) 0.2306 m

(B) 1.467 Hz

(C) 0.1152 m

Explanation:

spring constant (K) = 16.4 N/m

mass (m) = 0.193 kg

acceleration due to gravity (g) = 9.8 m/s^{2}

(A) force = Kx,  where x = extension

   mg = Kx

   0.193 x 9.8 = 16.4x

   x = 0.1153 m

  now the mass actually falls two times this value before it gets to its equilibrium position ( turning  point ) and oscillates about this point

therefore

2x = 0.2306 m

(B) frequency (f) = \frac{1}{2π} x \sqrt{\frac{k}{m}}

     frequency (f) = \frac{1}{2π} x \sqrt{\frac{16.4}{0.193}}

     frequency = 1.467 Hz  

(C) the amplitude is the maximum position of the mass from the equilibrium position, which is half the distance the mass falls below the initial length of the spring

= \frac{0.2306}{2} =  0.1152 m

8 0
3 years ago
Which objects have both potential and kinetic energy? Check all that apply.
wariber [46]
A falling raindrop
Kinetic energy and potential energy are both applied when a body or object is falling.
3 0
4 years ago
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Suppose a Heel-mobile, moving in a straight line and steadily increases its speed. It moves from 15 m/s to 30 m/s the first seco
Makovka662 [10]

acceleration = change in velocity/change in time  = 45-15 / 2

=30/2 = 15 m/s

6 0
3 years ago
The yellow wire connected to a power supply carries 12v. if the power supply provides 60w of power to the yellow wire, how much
saul85 [17]
In physics, the rate of power in Watts could be determined by multiplying the voltage in volts, by the current in Amperes. In equation, that would be

P = IV

Substituting the values into the equation,

60 W = I*12V
I = 60/12
I = 5 Amperes

Therefore, a current of 5 Amperes is passing through the yellow wire.
6 0
3 years ago
A small charged sphere is attached to a thread and placed in an electric field. The other end of the thread is anchored so that
VMariaS [17]

Answer:

E = 9.66\times 10^{-6} N/C

direction is Horizontal

Explanation:

As we know that the string is horizontal here

so the tension force in the string is due to electrostatic force on it

now we will have

F = qE

so here the force is tension force on it

F = 6.57 \times 10^{-2} N

Q = 6.80 \times 10^3 C

now we have

6.57 \times 10^{-2} = (6.80 \times 10^3)E

E = 9.66\times 10^{-6} N/C

direction is Horizontal

4 0
4 years ago
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