At point x = 0, the particle accelerates. Since there will be change of velocity at that point. The the force of the particle will change from negative sign to positive sign according to the given figure, we can therefore conclude that the particle will have a turning point at point x = 0.
Given that a 2.0 kg particle moving along the z-axis experiences the force shown in a given figure.
Force is the product of mass and acceleration. While acceleration is the rate of change of velocity. Both the force and acceleration are vector quantities. They have both magnitude and direction.
If the particle's velocity is 3.0 m/s at x = 0 m, that mean that the particle experience change of velocity at point x = 0. Since the the force of the particle will change from negative sign to positive sign according to the given figure, we can therefore conclude that the particle will have a turning point at point x = 0.
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Answer:
18 m
Explanation:
E = mgh
45 J = (0.25 kg) (9.8 m/s²) h
h = 18 m
Answer:

Explanation:
THE GIVEN sheet can be taken as two horizontal force with surface charge density is
at one surface is ∈_1 = 
at oher surface is ∈_2= 
the magnitude of electric field due to surface charge is given as
So, electric field at P (2 CM below from surface is) = E_1 +E_2



Answer:
v = 80.48 km/h.
Explanation:
We have,
Acceleration of a train is 2 km/h/s or 7200 km/h²
Initial velocity of a train is 20 km/h
It is required to find the velocity after 30 seconds or 0.0084 h
Let v is the final speed. Using equation of kinematics as :

So, the final speed of the train is 80.48 km/h.