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inna [77]
3 years ago
5

A 1.5 V battery is connected to a bulb of resistance of 4.5 Ω. What is the current in the bulb?

Physics
1 answer:
kogti [31]3 years ago
7 0

Answer:

0.333 A

Explanation:

R= V/l

R= 4.5 ohms

V = 1.5 volts

I=?

I = V/R

1.5/4.5 = 0.333 A

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DochEvi [55]

At point x = 0, the particle accelerates. Since there will be change of velocity at that point. The the force of the particle will change from negative sign to positive sign according to the given figure, we can therefore conclude that the particle will have a turning point at point x = 0.

Given that a 2.0 kg particle moving along the z-axis experiences the  force shown in a given figure.

Force is the product of mass and acceleration. While acceleration is the rate of change of velocity. Both the force and acceleration are vector quantities. They have both magnitude and direction.

If the particle's velocity is  3.0 m/s at x = 0 m, that mean that the particle experience change of velocity at point x = 0. Since the the force of the particle will change from negative sign to positive sign according to the given figure, we can therefore conclude that the particle will have a turning point at point x = 0.

Learn more here: brainly.com/question/20366032

6 0
3 years ago
Tabitha hit a 0.25 kg volleyball straight up into the air with 45 Joules of energy. How high did volleyball soar up? Round to th
zavuch27 [327]

Answer:

18 m

Explanation:

E = mgh

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h = 18 m

7 0
4 years ago
A huge (essentially infinite) horizontal nonconducting sheet 10.0 cm thick has charge uniformly spread over both faces. The uppe
TiliK225 [7]

Answer:

E = 6.77 *10^{3} N/C

Explanation:

THE GIVEN sheet can be taken as two horizontal force  with surface charge density is

at one surface is ∈_1 = 95*10^ {-9} C/mm2

at oher surface is ∈_2= -25*10^{-9} C/mm2

the magnitude of electric field due to surface charge is given as\frac{∈}{2∈_O}

So, electric field at P (2 CM below from surface is) = E_1 +E_2

E = \frac{∈_1}{2∈_O} +\frac{∈_2}{2∈_O}

E = \frac{95*10^{-9} +25*10^{-9}}{2*8.85*10^{-12}}

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8 0
4 years ago
Help me please this test is due today!
aleksley [76]

Answer:

v = 80.48 km/h.

Explanation:

We have,

Acceleration of a train is 2 km/h/s or 7200 km/h²

Initial velocity of a train is 20 km/h

It is required to find the velocity after 30 seconds or 0.0084 h

Let v is the final speed. Using equation of kinematics as :

v=u+at\\\\v=20+7200\times 0.0084\\\\v=80.48\ km/h

So, the final speed of the train is 80.48 km/h.

7 0
4 years ago
Read 2 more answers
What is the mass of an object that requires 100n of force in order to accelerate it at 10m/s^2
Shkiper50 [21]
100.10= 1000

the formula is:

f=m/t
4 0
3 years ago
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