Question

PART 3: The KINEMATIC EQUATION PROBLEMS/CALCULATIONS

Answer 1

The results of the calculation are as follows;

• The runners new speed is  25.7 m/s.
• The height is  50.2 m
• The velocity of the rock is 31.4 m/s.
• The initial velocity is 18.2 m/s

How do apply kinematics?

The term kinematics has to do with the study of motion without looking at the cause of motion which is force.

Now let us try to solve the problems;

v = u + at

v = final velocity

u = initial velocity

a = acceleration

t = time

v = 6.5 + (2.4 * 8)

v = 25.7 m/s

b) Given the formula

h = ut + 1/2gt^2

h = height

g = acceleration due to gravity

Thus;

h = 1/2gt^2 (because u = 0 m/s when the object is dropped from a height)

h = 0.5 * 9.8 * (3.2)^2

h = 50.2 m

c) v = u + gt

v = gt

v = 9.8 * 3.2

v = 31.4 m/s

d) v^2 = u^2 - 2gh

Now v = 0 m/s at the maximum height

Thus;

u^2 = 2gh

u = √2gh

u = √2 * 9.8 * 17

u = 18.2 m/s

Learn more about kinematics:brainly.com/question/7590442

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