Which symbol is used for an alpha particle? a. β c. γ b. Δ d. α

If an object accelerating at −1.5m/s^2 takes 1.2s to reach 5.0m/s, what was its initial speed?

USPshnik [31]

-1.5 m/s^2 x 1.2 seconds = -1.8 m/s

It is a negative value which means the object slowed down. The object would have originally been going that amount more.

5.0 + 1.8 = 6.8 m/s

answer: 6.8 m/s

3 0

1 year ago

A car's velocity changes from 40 m/s to 30 m/s in 40 seconds. What is the

valina [46]

Answer:

- 0.25m/s²

Explanation:

Given parameters:

Initial velocity = 40m/s

Final velocity = 30m/s

Time taken = 40s

Unknown:

Acceleration of the car = ?

Solution:

Acceleration is the rate of change of velocity with time.

So;

Acceleration = $\frac{Final velocity - Initial velocity }{time }$

Acceleration = $\frac{30 - 40}{40}$ = - 0.25m/s²

This implies that the car will decelerate at a rate of 0.25m/s²

7 0

2 years ago

How has God designed sound waves so that a person is able to hear all the different instruments in a musical piece at the same t

Tcecarenko [31]

Answer: when the wave encounters something, it can bounce (reflection) or be bent (refraction). In fact, you can "trap" waves by making them bounce back and forth between two or more surfaces. Musical instruments take advantage of this; they produce pitches by trapping sound waves.

Explanation: Any bunch of sound waves will produce some sort of noise. But to be a tone - a sound with a particular pitch - a group of sound waves has to be very regular, all exactly the same distance apart. That's why we can talk about the frequency and wavelength of tones.

8 0

2 years ago

Train cars are coupled together by being bumped into one another. Suppose two loaded cars are moving toward one another, the fir

tia_tia [17]

Answer:

7560 Joules

Explanation:

$m_1$ = Mass of first car = $1.5\times 10^5\ kg$

$m_2$ = Mass of second car = $2\times 10^5\ kg$

$u_1$ = Initial Velocity of first car = 0.3 m/s

$u_2$ = Initial Velocity of second car = -0.12 m/s

v = Velocity of combined mass

As linear momentum of the system is conserved

$m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\\\Rightarrow v=\frac{1.5\times 10^5\times 0.3 + 2\times 10^5\times -0.12}{1.5\times 10^5 + 2\times 10^5}\\\Rightarrow v=0.06\ m/s$

Energy lost is

$\Delta E=\Delta E_i-\Delta E_f\\\Rightarrow \Delta=\frac{1}{2}(m_1u_1^2 + m_2u_2^2-(m_1+m_2)v^2)\\\Rightarrow \Delta=\frac{1}{2}(1.5\times 10^5\times 0.3^2 + 2\times 10^5\times (-0.12)^2-(1.5\times 10^5 + 2\times 10^5)\times 0.06^2)\\\Rightarrow \Delta=7560\ J$

The Energy lost in the collision is 7560 Joules

7 0

2 years ago

In the development of atomic models, it was realized that the atom is mostly empty. Consider a model for the hydrogen atom where

Rama09 [41]

Answer:

Check the explanation

Explanation:

a) in solving the first question, we will be choosing a spherical ball of radius 1 m, Therefore the width of the object is the diameter = 2m.

b)Given that and according to the question, the radius of the electron's orbit = 1x105 x radius of the object = 1x105 x1 = 1x105 m

8 0

2 years ago