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castortr0y [4]
3 years ago
8

How much heat is needed to raise the temperature of 100 g of water by 50 C, if the specific heat of water is 4,184 J/kg.C?

Physics
1 answer:
Yuliya22 [10]3 years ago
4 0

Heat required to raise the temperature of water is given as

Q = ms\Delta T

here we have

m = 100 g = 0.100 kg

s = 4183 J/kg C

\Delta T = 50 ^0 C

now we can use the above equation

Q = 0.100 * 4184 * 50

Q = 20920 J

so here it requires 20920 J heat to raise the temperature of 100 g water by 50 degree C

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Nataly_w [17]

Answer:

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Explanation:

1. Determination of the equivalent resistance

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12 = 3 × Rₑq

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Thus, the equivalent resistance (Rₑq) = 4 Ω

2. Determination of R₂.

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Resistance 2 (R₂)

Since the resistor are in parallel arrangement, the value of R₂ can be obtained as follow:

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Cross multiply

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48 + 4R₂ = 12R₂

Collect like terms

48 = 12R₂ – 4R₂

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3. Determination of the total voltage (Vₜ), V₁ and V₂.

From the question given above, the total voltage is 12 V

Since the resistors are arranged in parallel connection, the same voltage will go through them.

Thus,

Vₜ = V₁ = V₂ = 12 V

4. Determination of the total current (Iₜ), I₁ and I₂

From the question given above, the total current (Iₜ) is 3 A

Next, we shall determine I₁. Since the resistors are arranged in parallel connection, different current will pass through each resistor respective.

Vₜ = V₁ = 12 V

R₁ = 12 Ω

I₁ =?

V₁ = I₁R₁

12 = I₁ ×12

Divide both side by 12

I₁ = 12 / 12

I₁ = 1 A

Next, we shall determine I₂. This can be obtained as follow:

Iₜ = 3 A

I₁ = 1 A

I₂ =?

Iₜ = I₁ + I₂

3 = 1 + I₂

Collect like terms

I₂ = 3 – 1

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