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nydimaria [60]
1 year ago
14

Use condensed electron configurations and Lewis electron-dot symbols to depict the ions formed from each of the following atoms,

and predict the formula of their compound:
(a) Cs and S
Chemistry
1 answer:
Dennis_Churaev [7]1 year ago
6 0

The formula for Cs and S is Cs₂S.

For Cs and S,

Ions formed will be Cs⁺ and S²⁻

As cesium belongs to group 1A and sulfur belongs to group 6A. Therefore, the condensed electronic configuration is -

For Cs is [Xe} 6s¹ and for S is [Ne] 3s²3p⁴.

Cs have 1 valence electron and S have 6 valence electrons.

Hence to attain a stable electronic configuration, both two Cs atoms lose one electron and form Cs⁺ and these two electrons will be accepted by one S atom to form S²⁻.

Therefore the formula for the compound is Cs₂S as Cs donate 1 electron and S will accept 2 electrons from Cs.

The formula is Cs₂S.

To learn more about electronic configuration, visit: brainly.com/question/15051483

#SPJ4

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Answer:

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Explanation:

The detailed steps and appropriate calculation is as shown in the attached file.

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The property is its polarity (or hydrogen bonds)
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What is the total number of ions in one formula unit of (NH4)2CO3?
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When 1 mole of ammonium carbonate is dissolved in water it gives

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4 0
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A sample of metal has a mass of 24.64 g, and a volume of 5.91 mL. What is the density of this metal?
dlinn [17]

Answer:

\boxed {\boxed {\sf 4.17 \ g/mL}}

Explanation:

We are asked to find the density of a metal. Density is the mass per unit volume. It is calculated by dividing the mass by the volume.

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The mass of the metal sample is 24.64 grams and the volume is 5.91 milliliters. We can substitute these values into the formula.

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\rho=\frac{24.64 \ g }{5.81 \ mL}

Divide.

\rho= 4.169204738 \ g/mL

The mass measurement has 4 significant figures the volume measurement has 3 significant figures. Our answer for density must match the least number of significant figures, which is 3.

For the number we calculated, that is the hundredth place. The 9 in the thousandth place tells us to round the 6 up to a 7.

\rho \approx 4.17 \ g/mL

The density of this metal is approximately <u>4.17 grams per milliliter.</u>

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