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3 years ago

Reagent needed to convert sulphur dioxide to Sulphur

1 answer:

5 0

6 + x = 12. To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12. If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.

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1. calculate the the reaction of gas, F 2 (g) with H 2 O(l) water form and O 2 (e).

Sever21 [200]

hope this helped.:)

Explanation:

Yes, the number of moles of oxygen gas produced by your reaction under those conditions for pressure and temperature will be 0.0025.

Hydrogen peroxide,

, decomposes to give water and oxygen gas according to the balanced chemical equation

(

)

→

(

)

(

)

You've collected 0.061 L of oxygen gas at 295.15 K and 1 atm, so you've got all the data you need to calculate the number of moles of oxygen gas produced by using the ideal gas law equation

⇒

atm

⋅

0.061

0.082

⋅

atm

mol

⋅

0.0025 moles

So, if this was your first question, then yes, your reaction produced 0.0025 moles of oxygen gas.

I find the second part of your question to be a little confusing. You were given the density of the hydrogen peroxide solution, so are you supposed to use that to determine the theoretical number of moles of oxygen for this reaction?

I'm not sure what

100%

1.02 g/mL

means, do you have a certain volume of hydrogen peroxide solution?

SIDE NOTE According to the additional information posted by Heather, it turns out that the initial hydrogen peroxide solution had a volume of 5 mL.

Even with the volume of the initial solution, you'd need its percent concentration to try and determine exactly how many moles you had present before the reaction.

Once you know how many moles of hydrogen peroxide you had, assume that all of the react and use the

mole ratio that exists between

and

to get the number of moles of oxygen your reaction could have produced.

7 0

3 years ago

In ionic bonding, atoms__.

Nutka1998 [239]

In ionic bonding, atoms SHARE ELECTRONS

8 0

2 years ago

Why does inhaled air need to be warmed filtered and moistened?

bearhunter [10]

The body has to do this to make sure and or to prevent damage to the delicate tissues that form the Respiratory System. This is important because Your body's organs, such as your heart and brain, need oxygen-rich blood to work well. (if it gets damaged by the Cold/Dry air you breath in on a daily)Respiratory failure also can occur if your lungs can't properly remove carbon dioxide (a waste gas) from your blood. Too much carbon dioxide in your blood can harm your body's organs.

Hopefully i helped ^.^ please mark brainly if its a possibility~

4 0

3 years ago

To determine the ammonia concentration in a sample of lake water, three samples are prepared. In sample A, 10.0 mL of lake water

Masteriza [31]

Answer:Sample Absorbance (625 nm)

A 0.536

B 0.783

C 0.045

Therefore, I will use these data to solve your question. If you have other absorbances values, just follow my steps and plug in different numbers.

First, we see 1 mole of NH3 gives 1 mole product.

In B moles of NH3 = moles of NH3 in A + (5.5 x10^-4 x2.5/1000) = 1.375 x10^6 + mA

( mA = moles of NH3 in A) vol of B = 25 = vol of A

now A = el C = eC ( since l = 1cm)

Because, n net absorbance due to complex blank absorbance must be removed.

Here A(A) = 0.536 - 0.045 = 0.491 , A(B) = 0.783 - 0.045 = 0.738

(you can plug in different numbers in this step)

A2/A1 = C2/C1 , A(B)/A(A) = (1.375x10^-6 +mA)/(mA) = 0.738/0.491

So, mA = 2.733 x 10^-6 = moles of NH3 in A (Lake water)

Hence [NH3] water ( 2.733 x10^-6 ) x 1000/25 = 1.093 x 10^-4 M

Lake water vol = 10 ml out of 25,

Concentration of ammonia in lake water = 2.733 x10^-6 x 1000/10 = 2.733 x 10^-4 M

Then, A = 0.491 = e x 1 x 1.093 x10^-4

e = 4492 M-1cm-1

Explanation:

4 0

3 years ago

What is the percent composition of nitrogen in a 2.57 g sample of Al(NO3)3?

Lisa [10]

Answer:

19.8% of Nitrogen

Explanation:

In the Al(NO₃)₃ there are:

1 atom of Al

3 atoms of N

And 9 atoms of O

The molar mass of Al(NO₃)₃ is:

1 Al * (26.98g/mol) = 26.98g/mol

3 N * (14g/mol) = 42g/mol

9 O * (16g/mol) = 144g/mol

26.98 + 42 + 144 = 212.98g/mol

We can do a conversion using these molar masses to find the mass of nitrogen is the sample, that is:

2.57g * (42g/mol / 212.98g/mol) =

0.51g N

Percent composition of nitrogen is:

0.51g N / 2.57g * 100

= 19.8% of Nitrogen

6 0

2 years ago