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ddd [48]
2 years ago
12

What is the total number of ions in one formula unit of (NH4)2CO3?

Chemistry
2 answers:
evablogger [386]2 years ago
7 0

Answer:

in the image above

+++++++++

hope this helps please mark me brainiest

Len [333]2 years ago
4 0

There are 3  ions in one formula unit of (NH4)2CO3.

Ions present in  Ammonium carbonate.(NH4)2CO3

(NH4)2CO3 is called Ammonium carbonate. The formula indicates that in one mole of ammonium carbonate, There are

  • Two moles of ammonium ions,NH₄⁺ with valency of +1.
  • 1 mole of Carbonate ions  CO₃²⁻  with valency of -2.

When 1 mole of ammonium carbonate is dissolved in water it gives

(NH₄)₂CO₃   ₊  H₂O---->2NH₄⁺    ₊  CO₃²⁻

Ions present are 2NH₄⁺   and CO₃²⁻

Learn more on (NH4)2CO3 here:brainly.com/question/2272720

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Sonja [21]

Explanation:

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4 0
2 years ago
How many atoms are in 9.95 moles of iron?
zvonat [6]

Answer:

59.92 × 10²³ atoms are in 9.95 moles of iron

1.8 ×10²² molecules are in 0.03 moles of Carbon dioxide

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6 0
2 years ago
If 16.29 grams of Na2SO4 is mixed with 3.697 grams of C and allowed to react according to the balanced equation: Na2SO4(aq) + 4
abruzzese [7]

<u>Answer:</u> The limiting reagent in the given chemical reaction is carbon metal.

<u>Explanation:</u>

Excess reagent is defined as the reagent which is present in large amount in a chemical reaction.

Limiting reagent is defined as the reagent which is present in small amount in a chemical reaction. Formation of product depends on the limiting reagent.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For sodium sulfate:</u>

Given mass of sodium sulfate = 16.29 g

Molar mass of sodium sulfate = 142 g/mol

Putting values in equation 1, we get:

\text{Moles of sodium sulfate}=\frac{16.29g}{142g/mol}=0.115mol

  • <u>For carbon:</u>

Given mass of carbon = 3.697 g

Molar mass of carbon = 12 g/mol

Putting values in equation 1, we get:

\text{Moles of carbon}=\frac{3.697g}{12g/mol}=0.31mol

For the given chemical reaction:

Na_2SO_4(aq.)+4C(s)\rightarrow Na_2S(s)+4CO(g)

By Stoichiometry of the reaction:

4 moles of carbon reacts with 1 mole of sodium sulfate

So, 0.31 moles of carbon will react with = \frac{1}{4}\times 0.31=0.0775mol of sodium sulfate

As, given amount of sodium sulfate is more than the required amount. So, it is considered as an excess reagent.

Thus, carbon metal is considered as a limiting reagent because it limits the formation of product.

Hence, the limiting reagent in the given chemical reaction is carbon metal.

4 0
3 years ago
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Mumz [18]

Answer:

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Explanation:

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