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Finger [1]
2 years ago
14

Solid a is a very hard electrical insulator in solid as well as in molten state and melts at extremely high temperature. What ty

pe of solid is it?.
Chemistry
1 answer:
velikii [3]2 years ago
3 0

This is covalent network type of solid.

For example, silicon dioxide (SiO₂) is covalent network solid with covalent bonding.

Covalent network solid is a chemical compound (or element) in which the atoms are bonded by covalent bonds in a continuous network extending throughout the material.

Silicon(IV) oxide has continuous three-dimensional network of SiO₂ units and diamond has sp3 hybridization.

This solids do not have free electrons so they are good insulators.

They have strong covalent bonds, so they melt at extremely high temperature.

Other examples are quartz, diamond, and silicon carbide.

More about network solid: brainly.com/question/15548648

#SPJ4

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Saltpeter is a compound made of potassium (k), nitrogen (n), and oxygen (o). every 100.00 g of saltpeter contains 38.67 g potass
xeze [42]
First, we need to compute the mass of oxygen found in 100 grams of saltpeter:
mass of oxygen = 100 - (mass of potassium + mass of nitrogen)
                          = 100 - (38.67 + 13.86)
                          = 100 - 52.53
mass of oxygen in 100 grams saltpeter = 47.47 grams

Now, we can use cross multiplication to find the mass of oxygen in 328 grams saltpeter as follows:
mass of oxygen = (328 x 47.47) / 100 = 155.7016 grams
5 0
3 years ago
Read 2 more answers
2LiOH + HNO3 → 2LINO3 + H2O<br> 1<br> Is it balanced
LiRa [457]

Answer:

no need to balance.....

3 0
3 years ago
Magnesium carbonate decomposes on heating to form magnesium oxide and carbon dioxide as shown.
lorasvet [3.4K]
C. 21.0g

that’s the aweeee
7 0
3 years ago
Calculate the molarity of a salt solution with a volume of 0.250L that contains 0.70 mol of NaCl. (SHOW WORK)
Kazeer [188]

Answer:

= 0.28M

Explanation:

data:

volume = 0.250 L

           = 0.250dm^3                       ( 1litre = 1dm^3)

moles = 0.70 moles

Solution:

      molarity = \frac{no. of moles}{volume in dm^3}

                 = 0.70 / 0.250

    molarity = 0.28 M

5 0
2 years ago
Air, with an initial absolute humidity of 0.016 kg water per kg dry air, is to be dehumidified for a drying process by an air co
amid [387]

Answer:

(a) The proportion of dry air bypassing the unit is 14.3%.

(b) The mass of water removed is 1.2 kg per 100 kg of dry air.

Explanation:

We can express the proportion of air that goes trough the air conditioning unit as p_{d} and the proportion of air that is by-passed as p_{bp}, being p_{d}+p_{bp}=1.

The amount of water that goes into the drier inlet has to be 0.004 kg/kg, and can be expressed as:

0.004 = 0.016*p_{bp}+ 0.002*p_{d}

Replacing the first equation in the second one we have

0.004 = 0.016*(1-p_{d})+ 0.002*p_{d}=0.016-0.016*p_{d}+0.002*p_{d}\\0.004 - 0.016 = (-0.016+0.002)*p_{d}\\-0.012 = -0.014*p_{d}\\p_{d}=\frac{-0.012}{-0.014}=0.857\\\\p_{bp}=1-p_{d}=1-0.857=0.143

(b) Of every kg of dry air feed, 85.7% goes in to the air conditioning unit.

It takes (0.016-0.002)=0.014 kg water per kg dry air feeded.

The water removed of every 100 kg of dry air is

100 kgDA*0.857*0.014 kgW/kgDA= 1.1998 \approx 1.2 kgW

It can also be calculated as the difference in humiditiy between the inlet and the outlet: (0.016-0.004=0.012 kgW/kDA) and multypling by the total amount of feed (100 kgDA).

100 * 0.012 = 1.2 kgW

7 0
4 years ago
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