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3 years ago

Wich statement describes how basic coffee cup calorimeter works

2 answers:

5 0

The correct answer is D) ) It uses the mass and specific heat of water along with a thermometer to measure the gain or loss of energy when a substance is added.

The statement that describes how a basic coffee cup calorimeter works is: "It uses the mass and specific heat of water along with a thermometer to measure the gain or loss of energy when a substance is added."

To measure the heat flow during a chemical reaction we use the device called Calorimeter. This device has a combustion chamber and above it, a metal container of water. With the use of a thermometer, we can measure the change in temperature. The combustion chamber releases the heat. This increases the temperature of the water.

The other options of the question were A) It measures the mass of a substance given the specific heat and temperature of water in a cup of known size. B) It measures the density of a substance given the mass, specific heat, and temperature of water in a cup of known size. C) It uses the mass and specific heat of water along with a pressure gauge to measure the gain or loss of energy when a substance is added.

lapo4ka [179]3 years ago

4 0

Answer:

Explanation:

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A certain indicator has a color chart that shows that when the indicator is yellow, the solution is acidic. What is true about a

bija089 [108]

It’s acidic?
It tastes sour
It has at least one hydrogen molecule

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3 years ago

Which equation is balanced?

vichka [17]

Answer:

2Na+F2 yields 2NaF is balanced.

Explanation:

There are 2 sodium and 2 fluorine in both reactants and product: In 2NaF the 2 is distributed because it is in the beginning of the compound.

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3 years ago

Read 2 more answers

I don’t really understand, if anybody can help I’ll really appreciate it ! Thank you.

Alex_Xolod [135]

Answer:

175

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2 years ago

If 287 mL of a 1.6 M glucose solution is diluted to 412 mL , what is the molarity of the diluted solution

satela [25.4K]

Answer:

The answer to your question is 1.11 M

Explanation:

Data

volume 1 = 287 ml

concentration 1 = 1.6 M

volume 2= 412 ml

concentration 2 = ?

Formula

Volume 1 x concentration 1 = Volume 2 x concentration 2

Solve for concentration 2

concentration 2 = (volume 1 x concentration 1) / volume 2

Substitution

concentration 2 = (287 x 1.6) / 412

Simplification

concentration 2 = 459.2 / 412

Result

concentration 2 = 1.11 M

5 0

3 years ago

Question List (4 items) (Drag and drop into the appropriate area) Find the volume of HCl that will neutralize the base. Find the

expeople1 [14]

The question is incomplete, the complete question is:

The solubility of slaked lime, $Ca(OH)_2$ , in water is 0.185 g/100 ml. You will need to calculate the volume of $2.50\times 10^{-3}$ M HCl needed to neutralize 14.5 mL of a saturated

<u>Answer:</u> The volume of HCl required is 290mL, the mass of $Ca(OH)_2$ is 0.0268g, the moles of

<u>Explanation:</u>

Given values:

Solubility of $Ca(OH)_2$ = 0.185 g/100 mL

Volume of $Ca(OH)_2$ = 14.5 mL

Using unitary method:

In 100 mL, the mass of $Ca(OH)_2$ present is 0.185 g

So, in 14.5mL. the mass of $Ca(OH)_2$ present will be = $\frac{0.185}{100}\times 14.5=0.0268g$

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Given mass of $Ca(OH)_2$ = 0.0268 g

Molar mass of $Ca(OH)_2$ = 74 g/mol

Plugging values in equation 1:

$\text{Moles of }Ca(OH)_2=\frac{0.0268g}{74g/mol}=0.000362 mol$

Moles of $OH^-$ present = $(2\times 0.000362)=0.000724mol$

The chemical equation for the neutralization of calcium hydroxide and HCl follows:

$Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O$

By the stoichiometry of the reaction:

Moles of $OH^-$ = Moles of $H^+$ = 0.000724 mol

The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}$ .....(2)

Moles of HCl = 0.000724 mol

Molarity of HCl = $2.50\times 10^{-3}$

Putting values in equation 2, we get:

$2.50\times 10^{-3}mol=\frac{0.000724\times 1000}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.000725\times 1000}{2.50\times 10^{-3}}=290mL$

Hence, the volume of HCl required is 290mL, the mass of $Ca(OH)_2$ is 0.0268g, the moles of

5 0

3 years ago