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Svet_ta [14]
3 years ago
15

Wich statement describes how basic coffee cup calorimeter works

Chemistry
2 answers:
dybincka [34]3 years ago
5 0

The correct answer is D) ) It uses the mass and specific heat of water along with a thermometer to measure the gain or loss of energy when a substance is added.

The statement that describes how a basic coffee cup calorimeter works is: "It uses the mass and specific heat of water along with a thermometer to measure the gain or loss of energy when a substance is added."

To measure the heat flow during a chemical reaction we use the device called Calorimeter. This device has a combustion chamber and above it, a metal container of water. With the use of a thermometer, we can measure the change in temperature. The combustion chamber releases the heat. This increases the temperature of the water.

The other options of the question were A) It measures the mass of a substance given the specific heat and temperature of water in a cup of known size. B) It measures the density of a substance given the mass, specific heat, and temperature of water in a cup of known size. C) It uses the mass and specific heat of water along with a pressure gauge to measure the gain or loss of energy when a substance is added.

lapo4ka [179]3 years ago
4 0

Answer:

D

Explanation:

I just took the quiz

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Mazyrski [523]

Answer:I just want points

Explanation:because I need them for future questions

6 0
2 years ago
A chemical reaction yields 3 moles of lithium hydroxide (LiOH). How many grams of
grin007 [14]

72g

Explanation:

Given parameters:

Number of moles of LiOH = 3moles

Unknown:

Mass of LiOH = ?

Solution:

A mole of  substance is a unit used to make quantitative measures in chemistry.

It is the amount of substance that contains the avogadro's number of particles.

The mole is related to mass using the expression below;

    Mass of a substance = number of moles x molar mass

Molar mass of LiOH = 7 + 16 + 1 = 24g/mol

 Mass of LiOH = 3 x 24 = 72g

learn more:

Number of moles brainly.com/question/1841136

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8 0
3 years ago
2CO + 2NO yields 2CO2 + N2 which element was oxidized
aalyn [17]
2C⁺²O⁻² + 2N⁺²O⁻² = 2C⁺⁴O⁻²₂ + N₂⁰

C⁺² → C⁺⁴ + 2e⁻

carbon was oxidized
5 0
3 years ago
Convert the following into balanced equations. ( Use the lowest possible coefficents)?(a) When gallium metal is heated in oxygen
ehidna [41]

Answer:

Explanation:

(a) Balanced reaction of gallium with oxygen is as follows:

4Ga(s)+3O_2(g) \rightarrow 2Ga_2O_3 (s)

(b) C_6H_{14}(l)+O_2(g)\rightarrow CO_2(g)+H_2O(l)

Multiply the carbon dioxide by 6 to balance carbon as follows:

C_6H_{14}(l)+O_2(g)\rightarrow 6CO_2(g)+H_2O(l)

After that multiply H2O by 7 to balance hydrogen as follows:

C_6H_{14}(l)+O_2(g)\rightarrow CO_2(g)+7H_2O(l)

Finally balance oxygen by multiplying O2 by 19/2. Therefore, balanced reaction is as follows:

C_6H_{14}(l)+\frac{19}{2} O_2(g)\rightarrow 6CO_2(g)+7H_2O(l)

(c) Na_3PO_4(s)+CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl

first balance calcium, by multiply CaCl_2 by 3 as follows:

Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl

After that balance phosphorous by multiplying Na_3PO_4 by 2 as follows:

2Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl

Finally balance Na by multiplying NaCl by 6. Therefore, balance reaction is as follows:

2Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+6NaCl

3 0
3 years ago
If the molecular weight of a semiconductor is 27.9 grams/mole and the diamond lattice constant is 0.503 nm, what is the density
adelina 88 [10]

Explanation:

The given data is as follows.

      Mass = 27.9 g/mol

As we know that according to Avogadro's number there are 6.023 \times 10^{26} atom present in 1 mole. Therefore, weight of 1 atom will be as follows.

            1 atoms weight = \frac{38}{6.023 \times 10^{26}}    

In a diamond cubic cell, the number of atoms are 8. So, n = 8 for diamond cubic cell.

Therefore, total weight of atoms in a unit cell will be as follows.

            = \frac{8 \times 27.9 g/mol}{6.023 \times 10^{26}}

            = 37.06 \times 10^{-26}

Now, we will calculate the volume of a lattice with lattice constant 'a' (cubic diamond) as follows.

                   = a^{3}

                   = (0.503 \times 10^{-9})^{3}

                   = 0.127 \times 10^{-27} m^{3}

Formula to calculate density of diamond cell is as follows.

               Density = \frac{mass}{volume}

                             = \frac{37.06 \times 10^{-26}}{0.127 \times 10^{-27} m^{3}}

                            = 2918.1 g/m^{3}

or,                         = 0.0029 g/cc       (as 1 m^{3} = 10^{6} cm^{3})

Thus, we can conclude that density of given semiconductor in grams/cc is 0.0029 g/cc.

4 0
3 years ago
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