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Goryan [66]
3 years ago
5

Which word equation best describes the following formula equation: 4Al + 302 + 2Al2O3?

Chemistry
2 answers:
liberstina [14]3 years ago
6 0

Answer:

Explanation:

The equation is not correctly written, so let's start with that.

4Al + 3O2 ====> 2Al2O3?

Totally correct, including the balance numbers, would be

4moles aluminum + 3 moles Oxygen ===> 2 moles of Aluminum Oxide

Anything else is incomplete.

o-na [289]3 years ago
5 0

Answer:

aluminum reacts with oxygen to produce aluminum oxide.

I hope this helps

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In the reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O, an equivalence point occurs when 29.43 mL of 0.1973 M NaOH is added to a 32.
Tamiku [17]
            moles NaOH = c · V = 0.1973 mmol/mL · 29.43 mL = 5.806539 mmol
            moles H2SO4 = 5.806539 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 2.9032695 mmol
Hence
            [H2SO4]= n/V = 2.9032695 mmol / 32.42 mL = 0.08955 M
The answer to this question is  [H2SO4] = 0.08955 M

6 0
3 years ago
Maricruz prepared 450 ml of 0.0085 M solution of sodium chloride. How many grams of NaCl did she need to make 0.450 L of 0.0085
Anton [14]

Answer:

Explanation:

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8 0
3 years ago
How many of the following statements about silver acetate, AgCH3COO, are true? i) More AgCH3CoO(S) will dissolve if the pH of th
shutvik [7]

Answer:

All three statements are true

Explanation:

Solubility equilibrium of silver acetate:

AgCH_{3}COO\rightleftharpoons Ag^{+}+CH_{3}COO^{-}

  • If pH is increased then concentration of H^{+} increases in solution resulting removal of CH_{3}COO^{-} by forming CH_{3}COOH. Hence, according to Le-chatelier principle, equilibrium will shift towards right. So more AgCH_{3}COO will dissolve
  • If AgNO_{3} is added then concentration of Ag^{+} increases in solution resulting shifting of equilibrium towards left in accordance with Le-chatelier principle. So less AgCH_{3}COO will dissolve
  • Insoluble precipitate of AgOH is formed by adding NaOH in solution resulting removal of Ag^{+}. So, more AgCH_{3}COO will dissolve

Hence all three statements are true

8 0
3 years ago
A student placed 18.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then
mamaluj [8]

Answer:

1.30464 grams of glucose was present in 100.0 mL of final solution.

Explanation:

Molarity=\frac{moles}{\text{Volume of solution(L)}}

Moles of glucose = \frac{18.5 g}{180 g/mol}=0.1028 mol

Volume of the solution = 100 mL = 0.1 L (1 mL = 0.001 L)

Molarity of the solution = \frac{0.1028 mol}{0.1 L}=1.028 mol/L

A 30.0 mL sample of above glucose solution was diluted to 0.500 L:

Molarity of the solution before dilution = M_1=1.208 mol

Volume of the solution taken = V_1=30.0 mL

Molarity of the solution after dilution = M_2

Volume of the solution after dilution= V_2=0.500L = 500 mL

M_1V_1=M_2V_2

M_2=\frac{M_1V_1}{V_2}=\frac{1.208 mol/L\times 30.0 mL}{500 mL}

M_2=0.07248 mol/L

Mass glucose are in 100.0 mL of the 0.07248 mol/L glucose solution:

Volume of solution = 100.0 mL = 0.1 L

0.07248 mol/L=\frac{\text{moles of glucose}}{0.1 L}

Moles of glucose = 0.07248 mol/L\times 0.1 L=0.007248 mol

Mass of 0.007248 moles of glucose :

0.007248 mol × 180 g/mol = 1.30464 grams

1.30464 grams of glucose was present in 100.0 mL of final solution.

4 0
4 years ago
Which temperature in Celsius (°C) does this thermometer show? –8° 0° 25° 32°
natka813 [3]

Answer:

0° Celsius

Explanation:

The thermometer shows 0° Celsius which corresponds to 32° F.

3 0
4 years ago
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