Question

A voltaic cell using Cu/Cu²⁺ and Sn/Sn²⁺ half-cells is set up at standard conditions, and each compartment has a volume of 345 mL. The cell delivers 0.17 A for 48.0 h.(b) What is the [Cu²⁺] remaining?

Answer 1

The remaining Cu2+ is 0.517 M .

Given ,

A volatile cell using Cu/Cu2+ and Sn/Sn2+ half cells is set up at standard conditions ,and each compartment has a volume of 345 ml .

Current = 0.17 A

Time = 48 hrs = 48 ( 3600) = 172800 s

we know , I = Q/t

thus , Q ,charge= It = 0.17 (17280) =29376 C

Then ,atomic mass of copper is 63 g

And valency of Cu is 2.

Thus , the equivalent mass of copper is 63/2 = 31.5

We know , 96500 coulombs of electricity produce copper = 31.5 g

29376 C of electricity produce copper =9.589 g

We know , 63.546 g of copper = 1 mol

9.589 g of copper = 0.1508 mol

We know ,

1 L  of  solution contains = 1 mole of Cu2+ ions

0.345 L of solution contains = o.345 moles of Cu2+ ions

the remaining Cu2+ ion in the solution is given by ,

total Cu2+ ions in the solution - copper deposited

= 0.345 mol - 0.152 mol =0.1942 mole of Cu2+

Thus , molarity ,M = 0.1942 mol/ 0.375L =0.517 M

Hence ,the remaining Cu2+ is 0.517 M  .

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