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3 years ago

Identify the hybridization of the n atom in nf3.

2 answers:

7 0

The hybridization would be sp2. it goes from s, sp, sp2, sp3, sp3d, and so on. each bond gets one more level. since there are three bonds connecting to nitrogen it would be sp2.

guapka [62]3 years ago

7 0

Answer:

sp3 hybridization

Explanation:

Hello,

Based on the Lewis structure Nitrogen has 3 valence electrons with a lone pair of non-bonded electrons, thus, the hybridization calculation rule,

$Hybridization=\#Attached.Atoms+\# lone.pairs\\$

Allows us to identify that the $NF_3$ has three attached atoms and one lone pair. Now, by considering the convention: sp3=4, sp2=3 and sp=2 , one finds that:

$Hybridization=3+1=4$

Therefore, $NF_3$ has sp3 hybridization.

Best regards.

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Heptane and water do not mix, and heptane has a lower density (0.684 g/mL) than water (1.00 g/mL). A 100-mL graduated cylinder w

kicyunya [14]

Answer:

$h=100.8cm$

Explanation:

Hello,

In this case, considering the density and mass of both water and heptane we first compute the volume of each one:

$V_{water}=\frac{m_{water}}{\rho _{water}}=\frac{34g}{1.00g/mL}=34mL\\ \\V_{heptane}=\frac{m_{heptane}}{\rho _{heptane}}=\frac{34.6g}{0.684g/mL}=50.6mL\\$

Now, the total volume is:

$V=50.6mL+34mL=84.6mL$

Which is equal to:

$V=84.6cm^3$

Then, by knowing that the volume of a cylinder is πr²h or π(D/2)²h, we solve for the height as follows:

$h=\frac{V}{\pi (D/2)^2} \\\\h=\frac{84.6cm^3}{\pi (3.16cm/2)^2} \\\\h=100.8cm$

Best regards.

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3 years ago