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3 years ago

Identify the hybridization of the n atom in nf3.

2 answers:

7 0

The hybridization would be sp2. it goes from s, sp, sp2, sp3, sp3d, and so on. each bond gets one more level. since there are three bonds connecting to nitrogen it would be sp2.

guapka [62]3 years ago

7 0

Answer:

sp3 hybridization

Explanation:

Hello,

Based on the Lewis structure Nitrogen has 3 valence electrons with a lone pair of non-bonded electrons, thus, the hybridization calculation rule,

$Hybridization=\#Attached.Atoms+\# lone.pairs\\$

Allows us to identify that the $NF_3$ has three attached atoms and one lone pair. Now, by considering the convention: sp3=4, sp2=3 and sp=2 , one finds that:

$Hybridization=3+1=4$

Therefore, $NF_3$ has sp3 hybridization.

Best regards.

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Na+ and Cl- __________ ___________________________ Na+ and PO4 3- __________ ___________________________ Na+ and SO4 2- ________

bagirrra123 [75]

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For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

The cations and anions being oppositely charged attract each other through strong coloumbic forces and form an ionic bond.

(1) Sodium is carrying +1 charge called as $Na^{+1}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $NaCl$ .

(2) Sodium is carrying +1 charge called as $Na^{+1}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $Na_3PO_4$ .

(3) Sodium is carrying +1 charge called as $Na^{+1}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $Na_2SO_4$ .

(4) Sodium is carrying +1 charge called as $Na^{+1}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $Na_2CO_3$ .

(5) Potassium is carrying +1 charge called as $K^{+1}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. They form $KCl$ .

(6) Potassium is carrying +1 charge called as $K^{+1}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. They form $K_3PO_4$ .

(7) Potassium is carrying +1 charge called as $K^{+1}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. They form $K_2SO_4$ .

(8) Potassium is carrying +1 charge called as $K^{+1}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. They form $K_2CO_3$ .

(9) Calcium is carrying +2 charge called as $Ca^{+2}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. They form $CaCl_2$ .

(10) Calcium is carrying +2 charge called as $Ca^{+2}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. They form $Ca_3(PO_4)_2$ .

(11) Calcium is carrying +2 charge called as $Ca^{+2}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. They form $CaSO_4$ .

(12) Calcium is carrying +2 charge called as $Ca^{+2}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. They form $CaCO_3$ .

(13) Ammonium ion is carrying +1 charge called as $NH_4^{+1}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. They form $NH_4Cl$ .

(14) Ammonium ion is carrying +1 charge called as $NH_4^{+1}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. They form $NH_4_3PO_4$ .

(15) Ammonium ion is carrying +1 charge called as $NH_4^{+1}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. They form $NH_4_2SO_4$ .

(16) Ammonium ion is carrying +1 charge called as $NH_4^{+1}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. They form $NH_4_2CO_3$ .