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kherson [118]
3 years ago
9

Identify the hybridization of the n atom in nf3.

Chemistry
2 answers:
alexgriva [62]3 years ago
7 0
The hybridization would be sp2. it goes from s, sp, sp2, sp3, sp3d, and so on. each bond gets one more level. since there are three bonds connecting to nitrogen it would be sp2.
guapka [62]3 years ago
7 0

Answer:

sp3 hybridization

Explanation:

Hello,

Based on the Lewis structure Nitrogen has 3 valence electrons with a lone pair of non-bonded electrons, thus, the hybridization calculation rule,

Hybridization=\#Attached.Atoms+\# lone.pairs\\

Allows us to identify that the NF_3 has three attached atoms and one lone pair. Now, by considering the convention: sp3=4, sp2=3  and sp=2 , one finds that:

Hybridization=3+1=4

Therefore, NF_3 has sp3 hybridization.

Best regards.

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What is the mass of HCL is consumed by the reaction of 1.5 mole of magnesium
photoshop1234 [79]

Answer: 109.5g

Explanation:

Mg + 2HCl —> MgCl2 + H2

From the equation,

1mole of Mg required 2moles of HCl

Therefore 1.5moles of Mg will require = 1.5 x 2 = 3 moles of HCl.

Molar Mass of HCl = 1+35.5 =36.5g/mol

Mass conc. Of HCl = 3 x 36.5 = 109.5g

3 0
3 years ago
What instrument is usually used to measure atmospheric pressure
geniusboy [140]
A machine called a barometer is what is used to measure atmospheric pressure :D
8 0
3 years ago
Read 2 more answers
A sample of gas has a density of 0.53 g/L at 225 K and under a pressure of 108.8 kPa. Find the density of the gas at 345 K under
sukhopar [10]

Answer:

\rho _2=0.22g/L

Explanation:

Hello!

In this case, since we are considering an gas, which can be considered as idea, we can write the ideal gas equation in order to write it in terms of density rather than moles and volume:

PV=nRT\\\\PV=\frac{m}{MM} RT\\\\P*MM=\frac{m}{V} RT\\\\P*MM=\rho RT

Whereas MM is the molar mass of the gas. Now, since we can identify the initial and final states, we can cancel out R and MM since they remain the same:

\frac{P_1*MM}{P_2*MM} =\frac{\rho _1RT_1}{\rho _2RT_2} \\\\\frac{P_1}{P_2} =\frac{\rho _1T_1}{\rho _2T_2}

It means we can compute the final density as shown below:

\rho _2=\frac{\rho _1T_1P_2}{P_1T_2}

Now, we plug in to obtain:

\rho _2=\frac{0.53g/L*225K*68.3kPa}{345K*108.8kPa}\\\\\rho _2=0.22g/L

Regards!

8 0
3 years ago
A neutral atom of which of the four element has the smallest radius
arsen [322]
Answer:
Element 1

Explanation:
The ionization energy is defined as the energy required to remove electrons from the atoms.
We know that the nucleus of the atom attracts the electrons, thus, bound these electrons to the atom.
This means that as the radius decreases, the force of attraction between the nucleus and the electron will increase, therefore, the energy required to remove the electron would increase (and vice-versa).

Based on the above, the atom with the smallest radius would be the atom with the largest first ionization energy.

Hope this help :)
6 0
3 years ago
Read 2 more answers
What is the mass of 1.71 ✕ 1023 molecules of h2so4?
Anuta_ua [19.1K]
The equation for calculating a mass is as follows:

m=n×M

Molar mass (M) we can determine from Ar that can read in a periodical table, and a number of moles we can calculate from the available date for N:

n(H2SO4)=N/NA

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Now we can calculate a mass of H2SO4:

m(H2SO4) = n×M = 0.3 × 98 = 27.8 g



7 0
3 years ago
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