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UNO [17]
3 years ago
5

In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is appro

ximately 2.15 106 m/s?
Chemistry
1 answer:
Zolol [24]3 years ago
8 0

This is an incomplete question, here is a complete question.

In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is approximately 2.15\times 10^6m/s?

Find the force acting on the electron as it revolves in a circular orbit of radius 5.34\times 10^{-11}m.

Answer : The force acting on electron is, 7.9\times 10^{-8}N

Explanation :

Formula used :

F=\frac{mv^2}{r}

where,

F = force acting on electrons

m = mass of electrons = 9.1\times 10^{-31}kg

v = speed of electron = 2.15\times 10^6m/s

r = radius of circular orbit = 5.34\times 10^{-11}m

Now put all the given values in the above formula, we get:

F=\frac{(9.1\times 10^{-31}kg)\times (2.15\times 10^6m/s)^2}{5.34\times 10^{-11}m}

F=7.9\times 10^{-8}N

Thus, the force acting on electron is, 7.9\times 10^{-8}N

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↪ Hello miss "galaxyu035" here's your answer for the question you wrote.

Answer :

No, <u>we cannot</u> stir silver nitrate solution with a copper spoon <u>because</u> , copper is more reactive than silver. Thus,it would displace silver from the silver nitrate solution forming copper nitrate.

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