Question

Plese HELP !!!

Answer 1

Answer:

-9/8

Step-by-step explanation:

$\frac{-2a^{-3}b^2}{a} \\ \\ =-\frac{2b^2}{a^4} \\ \\ =-\frac{2(3)^2}{(-2)^4} \\ \\ =-\frac{18}{16} \\ \\ =-\frac{9}{8}$