4 years ago

Perpendicular line equation to y=3/5x+1

1 answer:

3 0

Answer:

Find the negative reciprocal of the gradient, so 3 / 5 will switch its denominator with its numerator, and it will have the opposite sign.

So 3/5 will be - 5/3

Answer:

y = - 5 / 3x + 2

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sweet-ann [11.9K]

Hello!
When you have a non-exact root (irrational number)

$\sqrt{ \frac{3}{16} } \to \frac{ \sqrt{3} }{ \sqrt{16} } \to \boxed{\boxed{\frac{ \sqrt{3} }{4} }}\Longleftarrow(irrational\:number)\end{array}}\qquad\quad\checkmark$

7 0

3 years ago

A random sample of 65 bags of white cheddar popcorn weighed, on average, 5.74 ounces with a standard deviation of 0.26 ounce.

Marina86 [1]

Answer:

We failed to accept null hypothesis

Step-by-step explanation:

x= 5.74

Standard deviation = $0.26$

$H_0:\mu = 5.8\\H_a:\mu < 5.8$

n = 65

We will use z test

Formula : $z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

Substitute the values :

$z=\frac{5.74-5.8}{\frac{0.26}{\sqrt{65}}}$

$z=-1.86$

Refer the z table for p value

p value = 0.0314

α = 0.10

p value < α

So, we failed to accept null hypothesis

4 0

3 years ago

What is the constant of proportionality equation y=2.5x

RideAnS [48]

The Answer to your problem is X=0

4 0

2 years ago

Consider the following least-squares specification between test scores and the student-teacher ratio:

liraira [26]

Answer:

Option B

Step-by-step explanation:

Given that the regression equation using least squares for test scores and student teacher ratio is

Test Score = 557.8 + 36.42 In (Income).

Say if 1% income is increased.

Let income be 100

New income = 101

Then we have

Test score original =

$557.8+36.42 Ln 100\\= 725.520$

Test score new income

= $557.8+36.42 ln (101)\\= 725.882$

Increase = 0.362~0.36

Option B is right.

6 0

3 years ago

Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it.

Katarina [22]

Hope this helps you! :)

4 0

3 years ago