Question

Find the distance between (-6, -12) and (4,8) using the distance formula.

Answer 1

Answer:

The distance formula is 22.360679775

if you round it to the nearest tenth, then the answer is 22.4

Step-by-step explanation:

(-6, -12) and (4,8)

(x2 - x1)² + (y2 - y1)²

Place the x and y values

(4 - - 6)² + (8 - - 12)²

= 10² + 20²

= 100 + 400 = 500

√500 = 22.360679775

Round it to the nearest tenth, and you will get 22.4

Hope this helps!

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Answer 2

Answer: Distance = 10√2

Step-by-step explanation:

Given formula

$Distance~=~\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given information

(x₁, y₁) = (-6, -12)

(x₂, y₂) = (4, 8)

Substitute given information into the formula

$Distance~=~\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$Distance~=~\sqrt{((4)-(-6))^2+((8)-(-12))^2}$

Simplify values in the parenthesis

$Distance~=~\sqrt{(4+6)^2+(8+12)^2}$

$Distance~=~\sqrt{(10)^2+(20)^2}$

Simplify the exponents

$Distance~=~\sqrt{100+400}$

Simplify the radical number

$Distance~=~\sqrt{500}$

$Distance~=~\Large\boxed{10\sqrt{5}}$

Hope this helps!! :)

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