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makkiz [27]
4 years ago
13

Someone please help with this

Mathematics
1 answer:
netineya [11]4 years ago
7 0
This is the answer for the first and second question. I hope this helps :)

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Which equation represents a line that passes through (–9, –3) and has a slope of –6?
brilliants [131]
\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ -9}}\quad ,&{{ -3}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies -6
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-3)=-6[x-(-9)]
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y+3=-6(x+9)\implies y+3=-6x-54\implies y=-6x-57
8 0
3 years ago
This graph shows the cost of a small cheese pizza at 3 different restaurants. a) explain how the size of the bars gives a false
nlexa [21]

I would answer, but I don’t see the graph. If you add the graph I could help (if you want of course, not trying to be rude. Sorry!)

8 0
3 years ago
Estimate the quotient to the tenths place. Then find the quotient. Round to the nearest thousandth 3)1.066 The estimate is The q
riadik2000 [5.3K]

Answer:

Estimate = 0.4

Quotient = 0.355 ---> Approximated to nearest thousandth

Step-by-step explanation:

Question like this is better answered using attachment;

See Attachment

When 1.066 is divided by 3,

The quotient is 0.3553......

When estimating to tenths,

We stop the quotient at 0.35 then round it up.

This gives 0.4

When estimating to nearest thousandth,

We stop the quotient at 0.3553 then round it up;

This gives 0.355

7 0
3 years ago
Help me please ......
oksano4ka [1.4K]
-4 = x - 7
-4 + 7 = x
3 = x

Therefore x = 3
4 0
3 years ago
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1.rearrange your data from least to greatest:
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middle is 1 and 2 ... so median is 1+2/2= 1.5 and  it is the  median not the mean
2.I believe the only outlier is 50. Finding the mean would be 80.11.
<span>The answer would be D
</span>3.D. Mean always goes toward the skewness due to outliers.
<span>Median is minimally affected by outliers.
4.</span><span>We remove an outlier because we can simply assume that there was some type of extreme experimental error, or something went wrong. The mean shouldn't be effected that much, but the median will be greatly effected.</span>
3 0
3 years ago
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