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1 year ago

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the specific brain mass is the brain mass divided by the body mass. if body mass increases, does the specific brain mass increas

e or decrease?

1 answer:

Vikentia [17]1 year ago

3 0

The specific brain mass: decreases if body mass increases.

Due to the specific brain mass is the ratio of brain mass to body mass is inversely proportional when the body mass increases, the specific brain mass decreases.

If we calculate the specific brain mass of a person with a brain mass of 2 kg and a body mass of 50 kg and then with a body mass of 60 kg we have:

specific brain mass (50 kg) = 2 kg/50 kg = 0.04

specific brain mass (60 kg) = 2 kg/60 kg = 0.03

We can state that the specific brain mass decreases if the body mass increases.

<h3>What is body mass?</h3>

It is the amount of mass associated with a person's body

Learn more about body mass at: brainly.com/question/10091149

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(b) $4.19\times 1065\ Pa$

Explanation:

<u>Given:</u>

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<u>Assume:</u>

$P_2$ = The second pressure of air inside the tire

$P_3$ = The third pressure of air inside the tire
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Using the above equation for this part of compression in the air, we have

$\therefore \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\Rightarrow P_2 = \dfrac{V_1}{V_2}\times \dfrac{T_2}{T_1}\times P_1\\\Rightarrow P_2 = \dfrac{V_1}{0.3V_1}\times \dfrac{319}{283}\times 1.01325\times 10^5\\\Rightarrow P_2 =3.81\times 10^5\ Pa$

Hence, the pressure in the tire after the compression is $3.81\times 10^5\ Pa$ .

Part (b):

Again using the equation for this part for the air, we have

$\therefore \dfrac{P_2V_2}{T_2}=\dfrac{P_3V_3}{T_3}\\\Rightarrow P_3 = \dfrac{V_2}{V_3}\times \dfrac{T_3}{T_2}\times P_2\\\Rightarrow P_3 = \dfrac{V_2}{1.02V_2}\times \dfrac{358}{319}\times 3.81\times 10^5\\\Rightarrow P_3 =4.19\times 10^5\ Pa$

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