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rjkz [21]
3 years ago
11

Consider two planets in space that gravitationally attract each other. if the masses of both planets are doubled, and the distan

ce between them doesn't change, then the force between them is
Physics
2 answers:
amid [387]3 years ago
6 0
Yhuihoifjhh <span>F = Gm1m2 / r^2 

if the masses are doubled then the force is increased by a factor of 4 


if the distance is doubled the force is decreased by a factor of 1/ 2^2 
the net result is no change in force</span>
a_sh-v [17]3 years ago
4 0
Yhuihoifjhh F = Gm1m2 / r^2

if the masses are doubled then the force is increased by a factor of 4


if the distance is doubled the force is decreased by a factor of 1/ 2^2
the net result is no change in force
Hope this helps you! Please mark brainest!
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A traditional unit of length in Japan is the ken (1 ken 1.97 m). What are the ratios of (a) square kens to square meters and (b)
Roman55 [17]
If 1 ken is 1.97 meter, then 1 square ken is 3.8809 square meters, and one cubic ken is 7.645373. As for the cylindrical tank, the volume of it would be 10.835 times the radius of the cylinder time 1.97^2 times pi. As you didn't specify the radius, I can't give the exact answer but that would be how to get it.
7 0
3 years ago
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Conduction is usually faster/slower in liquids and certain solids than in gases.
KIM [24]
Conduction is slower in liquids and gases.

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6 0
3 years ago
John ( body mass= 65 kg) is taking off for a long jump . Horizontal accerleration ax is 5m/s^2 and vertical acceleration ay is 0
cestrela7 [59]

Answer:

(a) The horizontal ground reaction force  F_{g,x}=325\, N

(b)  The vertical ground reaction force F_{g,y}=696\, N

(c)   The resultant ground reaction force F_g=768\, N

Explanation:  

Given

John mass , m = 65 kg

Horizontal acceleration , a_x= 5.0 \frac{m}{s^{2}}

Vertical acceleration , a_y=0.9 \frac{m}{s^{2}}

(a) Using Newton's 2nd law in horizontal direction

F_{g,x}=ma_x

=>F_{g,x}=65\times 5\, N=325\, N

Thus the horizontal ground reaction force  F_{g,x}=325\, N

(b) Using Newton's 2nd law in vertical direction

F_{g,y}-mg=ma_y

=>F_{g,y}=mg+ma_y

=>F_{g,y}=65\times (9.81+0.9)\, N=696\, N

Thus the vertical ground reaction force F_{g,y}=696\, N

(c)  Resultant ground reaction force is

F_g=(F_{g,x}^{2}+F_{g,y}^{2})^{\frac{1}{2}}

=>F_g=(325^{2}+696^{2})^{\frac{1}{2}}\, N=768\, N

=>F_g=768\, N

Thus  the resultant ground reaction force F_g=768\, N

5 0
3 years ago
How far can your little brother get if he can travel at 2.5 m/s and in 5?
KatRina [158]

d=? v=2.5 u=0 and t=5 therefore the formula to be used to find the distance my brother covered is d=1/2(v-u)t

d=1/2(2.5-0)5

=6.15m

4 0
2 years ago
List atleast 10 applications of chemical effect of electric current
Komok [63]

Answer:

formation of gas bubbles at electrodes

deposition of metals at electrodes

changes in solution colour

electroplating

electrolysis

4 0
3 years ago
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