Answer:
tan (x eˣ) + C
Explanation:
∫ (eˣ + x eˣ) / (cos² (x eˣ)) dx
First, use u-substitution.
u = x eˣ
du = (eˣ + x eˣ) dx
∫ 1 / (cos² u) du
∫ sec² u du
tan u + C
Substitute back:
tan (x eˣ) + C
By Newton's Law of Universal Gravitation.
F = GMm/r²
Where F is Force of Gravitation, M = Mass of first object, m = mass of second object, r = distance of separation
From the formula, you can see that if the masses, M and m, increased, the value of F would definitely increase as well.
And if r increased the value of F would be reduced because you would be dividing by a bigger number, but when the value of r is decreased the value of F would be increased, because you would then be dividing by something smaller. Note the r is at the denominator of the formula.
So F would increase if there was increase in Masses and decrease in distance.
So the answer is C. a and b.
Explanation:
You can simply subtract the atomic number from the mass number in order to find the number of neutrons. If the atom is neutral, the number of electrons will be equal to the number of protons.
Remember!
1. Your mass number is the total number of neutrons and protons within the atom.
2. Your atomic number is the amount of protons within the atom.
3. For neutral atoms, the electron number is the same as the atomic number.
Answer:
Magnification, m = 3
Explanation:
It is given that,
Focal length of the lens, f = 15 cm
Object distance, u = -10 cm
Lens formula :
v is image distance
Magnification,
So, the magnification of the lens is 3.
Answer:
(a) The magnitude of the force electric force F = k ×(+Q) × (-2·Q)/r₀² = -2·Q²/(r₀²) which can be written as follows;
Given that the charge of Y is twice the charge on X, we have the charge X will move towards the charge Y which is the +x direction
(b) The force, F, acting between the charges is given as follows;
When, Q₁ = X = -4Q, Q₂ = Y = -2Q, and r₀ = 2·r₀ we have;
Therefore, the electric force exerted on object Y by the object X is the same and acts in an opposite direction to the force of X on Y in (a)
The net charge of the two objects in part (a) is Q - 2Q = -Q
The net charge of the two objects in part (b) is -4Q - 2Q = -6Q
Therefore, the net charge increases by a factor of 6 in part (b)
Explanation: