Does anyone know evaluate version
1 answer:
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In order to make 119$ he would need to work 7 hours
Question 1
Distributing 2 on 5y -2, we will get
But student get
So the student make an error in step 2 .
Second question
To get rid of y, we have to multiply first equation by -8 and add the resultant equation with equation Q .
Solution/Answer : 4
Solution: the first you do is multiply the last two parentheses to get -10xy
Now we are left with ( -2/5x)(-10xy)
Then we multiply that out into
(-2*-10)/5*x^2y = 20/5x^2y =
4x^2y
The coefficient in this case would be four. (In case you were confused about what a coefficient actually is, it’s the number you multiply a variable by)
Hopes this helps :)
Solution: the first you do is multiply the last two parentheses to get -10xy
Now we are left with ( -2/5x)(-10xy)
Then we multiply that out into
(-2*-10)/5*x^2y = 20/5x^2y =
4x^2y
The coefficient in this case would be four. (In case you were confused about what a coefficient actually is, it’s the number you multiply a variable by)
Hopes this helps :)