common difference is
3.6 - 5.8 = -2.2
let T1 = 5.8
T2 = 3.6
assuming we are to find T2
T2 = T(2-1) -2.2
= T1 -22
= 5.8 -2.2
= 3.6
5x2 + 4x + 4
Hope this helps!!!!!
Brainliest plzzzzz
3x + 4y = 38 ( equation 1) ----> ×5
5x - 5y = -30 ( equation 2) ----> ×3
When you multiply eqn 1 by 5 you get, 15x + 20y = 190
And when you multiply eqn 2 by 3, you get, 15x - 15y = -90
Then you solve both equations by subtracting eqn 2 from eqn 1
15x + 20y = 190
15x - 15y = 90
Then 15x - 15x gets cancelled and 20y - (-15y) gives 35y and 190 - (-90) gives 280.
So that gives 35y = 280
y = 8
And when you replace y = 8 in any of the two equations, x = 2
Answer:
No, the graph is only increasing while the student rides his bike, rides the bus, and walks. It is stays the same while he waits for the bus and when the bus stops to let him off.
Step-by-step explanation:
