The answer is (4x-5)(5x^2+1)
Answer:
14 cm
Step-by-step explanation:
Given:
A mug can hold 13.46 oz of coffee.
The radius of the mug is 3 cm.
Given that 1
equals 0.034 oz.
Question asked:
What is the height of the mug to the nearest centimeter ?
Solution:
Given that 1
equals 0.034 oz.
By unitary method:
0.034 oz = 1 
1 oz = 
13.46 oz =
A mug can hold 13.46 oz of coffee means volume of cylinder is given which is 395.88
. Now we can find the height of the mug by using volume of cylinder formula:
volume of cylinder = 

By cross multiplication:

By dividing both side by 198

Therefore, height of the mug to the nearest centimeter is 14 cm.
You can try to show this by induction:
• According to the given closed form, we have
, which agrees with the initial value <em>S</em>₁ = 1.
• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

and

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

From the given recurrence, we know

so that






which is what we needed. QED
Since the block is a cube, the dimentions from corner to corner equal all the same, as long as the pieces are equal, which in this case, they are. :) So basically what you need to do is find the perimeter of one side of the cube, and that's the answer.