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3 years ago

Someone knows this ??

Mathematics

1 answer:

Dima020 [189]3 years ago

8 0

Answer: A (1)

Explanation:

a(11) means column 1, row 1. Therefore, the answer would be the top left value.

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Find the measures of the interior

Ainat [17]

Answer:

Angle 1 = 108°

Angle 2 = 72°

Angle 3 = 120°

Angle 4 = 96°

Angle 5 = 144°

Step-by-step explanation:

We need to find the measures of the interior angles in a pentagon if the measure of each consecutive angle is in the ratio 9:6:10:8:12.

Let x be the common ratio

So, we can write:

Angle 1 = 9x

Angle 2 = 6x

Angle 3 = 10x

Angle 4 = 8x

Angle 5 = 12x

We know that the sum of all angles of pentagon = 540

So, adding all angles and equal them to 540, we can find value of x

$9x+6x+10x+8x+12x=540\\45x=540\\x=\frac{540}{45}\\x=12$

So, we get the value of x: x=12

Now, calculating the angles by putting x=12:

Angle 1 = 9x = 9(12) = 108°

Angle 2 = 6x = 6(12) = 72°

Angle 3 = 10x = 10(12) = 120°

Angle 4 = 8x = 8(12) = 96°

Angle 5 = 12x= 12(12) = 144°

6 0

3 years ago

Given: △RST ~ △VWX

tatiyna

Answer:

Given

Step-by-step explanation:

Given that: △RST ~ △VWX, TU is the altitude of △RST, and XY is the altitude of △VWX.

Comparing △RST and △VWX;

TU ~ XY (given altitudes of the triangles)

<TUS = <XYW (all right angles are congruent)

<UTS ≅ <YXW (angle property of similar triangles)

Thus;

ΔTUS ≅ ΔXYW (congruent property of similar triangles)

<UTS + <TUS + < UST = <YXW + <XTW + <XWY = $180^{0}$ (sum of angles in a triangle)

Therefore by Angle-Angle-Side (AAS), △RST ~ △VWX

So that:

$\frac{TU}{XY}$ = $\frac{US}{YW}$ (corresponding side length proportion)

4 0

3 years ago

Consider the function f(x)equalscosine left parenthesis x squared right parenthesis. a. Differentiate the Taylor series about 0

dybincka [34]

I suppose you mean

$f(x)=\cos(x^2)$

Recall that

$\cos x=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{x^{2n}}{(2n)!}$

which converges everywhere. Then by substitution,

$\cos(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{(x^2)^{2n}}{(2n)!}=\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n)!}$

which also converges everywhere (and we can confirm this via the ratio test, for instance).

a. Differentiating the Taylor series gives

$f'(x)=\displaystyle4\sum_{n=1}^\infty(-1)^n\frac{nx^{4n-1}}{(2n)!}$

(starting at $n=1$ because the summand is 0 when $n=0$ )

b. Naturally, the differentiated series represents

$f'(x)=-2x\sin(x^2)$

To see this, recalling the series for $\sin x$ , we know

$\sin(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^{n-1}\frac{x^{4n+2}}{(2n+1)!}$

Multiplying by $-2x$ gives

$-x\sin(x^2)=\displaystyle2x\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n+1)!}$

and from here,

$-2x\sin(x^2)=\displaystyle 2x\sum_{n=0}^\infty(-1)^n\frac{2nx^{4n}}{(2n)(2n+1)!}$

$-2x\sin(x^2)=\displaystyle 4x\sum_{n=0}^\infty(-1)^n\frac{nx^{4n}}{(2n)!}=f'(x)$

c. This series also converges everywhere. By the ratio test, the series converges if

$\displaystyle\lim_{n\to\infty}\left|\frac{(-1)^{n+1}\frac{(n+1)x^{4(n+1)}}{(2(n+1))!}}{(-1)^n\frac{nx^{4n}}{(2n)!}}\right|=|x|\lim_{n\to\infty}\frac{\frac{n+1}{(2n+2)!}}{\frac n{(2n)!}}=|x|\lim_{n\to\infty}\frac{n+1}{n(2n+2)(2n+1)}$

The limit is 0, so any choice of $x$ satisfies the convergence condition.

3 0

4 years ago

Sarah’s mom took 3 hours to clean, but when Sarah helped, it took them 2 hours to clean. How many hours will it take Sarah to cl

Aleonysh [2.5K]

Answer:

It takes them 1.875 hours.

Step-by-step explanation:

Here, the job is cleaning the house.

Mom does 1 job in 3 hours.

In 1 hour, mom does 1/3 of the job.

Dad does 1 job in 5 hours.

In 1 hour, dad does 1/5 of the job.

Mom and dad working together do the job in x hours.

In 1 hour, mom and dad together do 1/x of the job.

1/3 + 1/5 = 1/x

5/15 + 3/15 = 1/x

8/15 = 1/x

8x = 15

x = 15/8 = 1.875

Answer: It takes them 1.875 hours.

your welcome

6 0

2 years ago

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MULTIPLE CHOICE QUESTION ers What is 0.25 as a fraction?

DanielleElmas [232]

$\frac{1}{4}$

Hope it helps

4 0

3 years ago

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