Answer:
The answer is "3"
Step-by-step explanation:
In the question, some of the data is missing which is defined in the attached file. please find it.
That's why 3 is correct.
When finding the domain of a square root, you have to know that it is impossible to get the square root of 0 or any negative number. since domain is possible x values this means that x cannot be 0 or any number less than 0. However, you can find the square root of the smallest most infinitely small number greater than 0. since an infinitely small number close to zero can not be written out, we must must say that the domain starts at 0 exclusive. exclusive is represented by an open or close parenthesis so in this case the domain starts with:
(0,
we can get the square root of any number larger than 0 up to infinity but infinity can never be reached so it is also exclusive. So so the ending of our domain would be:
,infinity)
So the answer if the square root is only over the x the answer is
(0, infinity)
But if the square root is over the x- 5 then this would brIng a smaller amount of possible x values. since anything under the square root sign has to be greater than 0, you can say that:
(x - 5) > 0
x > 5
Therefore the domain would start at 5 and the answer would be:
(5, infinity)
Answer:
Step-by-step explanation:
Have in mind the definition of the term 
, and now work on what the term 
is based on the previous definition:
In the next step do NOT combine the numerical values, but try to identify the 
term (
) in the expression (notice the use of square brackets to group the relevant terms):
![a_{n+1}=4\,n+4-1\\a_{n+1}=[4\,n-1]+4\\a_{n+1}=a_n+4](https://tex.z-dn.net/?f=a_%7Bn%2B1%7D%3D4%5C%2Cn%2B4-1%5C%5Ca_%7Bn%2B1%7D%3D%5B4%5C%2Cn-1%5D%2B4%5C%5Ca_%7Bn%2B1%7D%3Da_n%2B4)
So now we have the term "" defined in a recursive manner based on the previous term ""
