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balandron [24]
3 years ago
8

A basketball coach asks half of his players to stretch before each game; the other players do not stretch. After a month of game

s, she analyzes their playing stats. She concludes the stretching helped improve their performance on the court. How can the coach test the means to be sure the results not likely to happen by chance? Answers are in the photo!

Mathematics
1 answer:
arlik [135]3 years ago
5 0

Answer:

C

Step-by-step explanation:

If the coach repeats the experiment, she will get more accurate results. This is because the more subjects (in this case, players), the more people to test on, and the lesser chance of an outlier (in this case, someone with abnormally high or low performance).  

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6. Let A and B be nxn matrices . Compute (A + B) (A + B). Explain all steps.
Pie

Answer:

(A+B)(A+B)=A.A+B.A+A.B+B.B

Step-by-step explanation:

Given that matrices A and B are nxn matrices

We need to find (A+B)(A+B)

For understanding the multiplication of matrices let'take A is mxn and B is pxq matrices,we can multiple only when n=p,so our Ab matrices will be mxq.

We know that that in matrices AB is not equal to BA.

Now find  

(A+B)(A+B)=A.A+B.A+A.B+B.B

So from we can say that (A+B)(A+B) is not equal to A.A+2B.A+B.B because AB is not equal to BA in matrices.

So (A+B)(A+B)=A.A+B.A+A.B+B.B

4 0
3 years ago
Classify the following triangle as acute
BaLLatris [955]
It is an acute triangle since all the sides are less than 90 degrees (it's also equilateral)
8 0
3 years ago
Find the perimeter of a ruler that measures 6 inches by 5/6
alukav5142 [94]

Answer:

41/3

Step-by-step explanation:

6 + 6 + 5/6 + 5/6

3 0
3 years ago
The GCF of 28 and 64 is<br><br> 2<br> 4<br> 7<br> 8
konstantin123 [22]
The greatest comment factor of 28 and 64 is 4.

The factors of 28 are 28, 14, 7, 4, 2, 1.
The factors of 64 are 64, 32, 16, 8, 4, 2, 1.

The common factors of 28 and 64 are 4, 2.

the greatest one of the two factors is 4.
8 0
3 years ago
Read 2 more answers
The diagram shows the cross-section of a wall of a cinema. It has to be painted. Work out the area that needs to be painted.
mestny [16]

Answer:

Area = 370 m²

Cost to paint = £105

Step-by-step explanation:

Area of the wall of a cinema hall = Area of a trapezoid (1)+ Area of a rectangle (2) + Area of a trapezoid (3)

Area of a trapezoid = \frac{1}{2}(b_1+b_2)h

where b_1 and b_2 are the parallel sides and h is the distance between these sides.

Area of trapezoid (1) = \frac{1}{2}(11+12)\times 6

                                  = 69 m²

Area of the rectangle (2) = Length × Width

                                         = 12 × 15

                                         = 180 m²

Area of the trapezoid (3) = \frac{1}{2}(12+10)\times 11

                                         = 121 m²

Now area of the wall = 69 + 180 + 121

                                   = 370 m²

One tin covers the area = 25 m²

Number of tins required to paint the wall = \frac{\text{Total area}}{\text{Area covered by one tin}}

= \frac{370}{25}

= 14.8

Therefore, number of tins to be purchased = 15

Cost to paint the complete wall = 15 × £7

                                                       = £105

8 0
3 years ago
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