Answer:
133.33g
Step-by-step explanation:
Let the:
Mass of 1.2g/cm³ of liquid = x
Mass of 1.8g/cm³ of liquid = y
From our Question above, our system of equations is given as:
x + y = 400........ Equation 1
x = 400 - y
1.2 × x + 1.8 × y = 1.6 × 400
1.2x + 1.8y = 640..... Equation 2
We substitute, 400 - y for x in Equation 2
1.2(400 - y) + 1.8y = 640
480 - 1.2y + 1.8y = 640
- 1.2y + 1.8y = 640 - 480
0.6y = 160
y = 160/0.6y
y = 266.67 g
Solving for x
x = 400 - y
x = 400 - 266.67g
x = 133.33g
Therefore, the mass of the liquid of density 1.2g/cm³ is 133.33g
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Answer:
Step-by-step explanation:
a) You go about this by using the given equation.
Left + Right = Total
JK + KL = JL
(2x -3) + 11 = 4x
8 = 2x . . . . . simplify, subtract 2x
4 = x . . . . . . divide by 2
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b) JL = 4x = 4·4
JL = 16
The sum of the interior angles of a triangle is 180. Add the three measures given and if you get 180 then those can be the interior angles of a triangle.
is it 1 + 2=3. are is it 2+1=3. are you a boy are not
Answer:
2 batches
Step-by-step explanation:
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