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2 years ago

What is the domain of h?

Mathematics

1 answer:

sergeinik [125]2 years ago

3 0

Answer:

Step-by-step explanation:

The domain is all the x numbers for each point
So -5,-4,0,2,4

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Find the term indicated in the expansion. (x - 3y)11; 8th term

Alja [10]

The term in the expansion:
T ( k+1) = n C k * A^(n-k) * B^k.
In this case: n = 11, k + 1 = 8, so k = 7.
A = x, B = - 3 y
T 8 = 11 C 7 * x^(11-7) * ( - 3 y )^7 =
=( 11 *10 * 9 * 8 * 7 * 6 * 5 ) / ( 7 * 6 * 5 * 4 * 3 * 2 * 1 )* x^4 * ( - 2,187 y^7 ) =
= 330 * ( - 2,187 ) x^4 y^7 = - 721,710 x^4 y^7
Answer: The 8th term in expansion is

8 0

2 years ago

Read 2 more answers

What is the sum of 1.3 and 5.07

love history [14]

Answer:

The asnwer is 6.37 y

Step-by-step explanation:

You have to add them sum means addition

I hope this helps

5 0

2 years ago

If i made 280 a month how much would i have in a year

Lorico [155]

Answer:

3360 dollars

Step-by-step explanation:

280 x 12 = 3360

3 0

2 years ago

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Find the right quotient. 36m 5 n 5 ÷ (12m 3)

polet [3.4K]

ANSWER

The right quotient is

$3 {m}^{2} {n}^{5}$

EXPLANATION

The given expression is :

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} }$

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} } = \frac{36}{12} \times \frac{ {m}^{5} }{ {m}^{3}} \times {n}^{5}$

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} } = 3\times \frac{ {m}^{5} }{ {m}^{3}} \times {n}^{5}$

Recall that,

$\frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n}$
We apply this property to obtain;

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} } = 3 \times {m}^{5 - 3} \times {n}^{5}$

$\frac{36 {m}^{5} {n}^{5} }{12 {m}^{3} } = 3 {m}^{2} {n}^{5}$

5 0

2 years ago

Read 2 more answers

Can anyone Help I have 25 questions, 2hr 40mins remaining,

11Alexandr11 [23.1K]

Combining the like-terms, the result of the addition of polynomials f(x) and g(x) is given by:

$f(x) + g(x) = 21x^3 + \frac{5}{4}x^{\frac{1}{2}} + 19x^{-\frac{1}{4}} + 8x^{-4}$

<h3>How do we add polynomials?</h3>

We add polynomials combining the like-terms, that is, adding terms with the same exponent.

In this problem, the polynomials are:

$f(x) = 3x^{\frac{1}{2}} + 7x^{-\frac{1}{4}} + 8x^{-4}$

$g(x) = -\frac{7}{4}x^{\frac{1}{2}} + 12x^{-\frac{1}{4}} - 21x^3$

Combining the like terms, the addition is given by:

$f(x) + g(x) = \left(3 - \frac{7}{4}\right)x^{\frac{1}{2}} + (7 + 12)x^{-\frac{1}{4}} + 8x^{-4} + 21x^3$

$f(x) + g(x) = 21x^3 + \frac{5}{4}x^{\frac{1}{2}} + 19x^{-\frac{1}{4}} + 8x^{-4}$

More can be learned about addition of polynomials at brainly.com/question/9438778

#SPJ1

8 0

1 year ago