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denis23 [38]
3 years ago
8

Reduce to simplest form. -3/5 plus 1/3​

Mathematics
1 answer:
Vilka [71]3 years ago
4 0
-4/15 is the answer
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Need help please (: Show how to apply the order of operation rules as you simplify the following expression
Gwar [14]

Apply in this order Ι-15Ι - 33÷11= 15-3=12


Good luck!!!


7 0
3 years ago
50 POINTS !!<br><br><br> PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.
Vesna [10]

Answer:

think its 1.10? tbh thats probably wrong

4 0
3 years ago
What is the solution to the system of liner equations shown on the graph?
Valentin [98]

Answer:

C The system has no solution

Step-by-step explanation:

They are parallel lines so there is no solution :).

5 0
3 years ago
The blood cholesterol levels of men aged 55 to 64 are approximately normally distributed with mean 222 mg/dl and standard deviat
tatiyna

Answer:

It is provided that 10% of the men aged 55 to 64 have cholesterol level <u>270 mg/dl</u> or higher.

Step-by-step explanation:

Let <em>X</em> = blood cholesterol levels of men aged 55 to 64 years.

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 222 mg/dl and standard deviation <em>σ</em> = 37 mg/dl.

It is provided that 10% of the men aged 55 to 64 have cholesterol level <em>x</em> mg/dl or higher.

Compute the value of <em>x</em> as follows:

P(X\geq x)=0.10\\P(\frac{X-\mu}{\sigma}\geq \frac{x-222}{37})=0.10\\P(Z\geq z)=0.10\\1-P(Z

Use the <em>z</em>-table to compute the value <em>z</em> for the probability 0.90.

The value of <em>z</em> is 1.29.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\1.29=\frac{x-222}{37} \\x=222+(1.29\times37)\\=269.73\approx270

Thus, 10% of the men aged 55 to 64 have cholesterol level 270 mg/dl or higher.

3 0
3 years ago
The speeds of vehicles traveling on a highway are normally distributed with an unknown population mean and standard deviation. I
Artemon [7]

Answer:

The t-score of 2.715 should be used

Step-by-step explanation:

Degrees of freedom ==> n - 1 ==> 38 - 1 ==> 37

to find 99% confidence interval,  Hence,

Find t0.005 in front of 37 degrees of freedom,

Therefore the answer is, t-score = 2.715

5 0
4 years ago
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