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2 years ago

synergistic interlayer and defect engineering in vs2 nanosheets toward efficient electrocatalytic hydrogen evolution reaction

1 answer:

4 0

It is stated that VS2 nanosheets with abundant defects and an extended (001) interlayer spacing as large as 1.00 nm, which is a 74% expansion as compared to that (0.575 nm) of the pristine counterpart, may be produced using a straightforward one-pot solvothermal process.

For the electrocatalytic hydrogen evolution reaction (HER), the interlayer expanded VS2 nanosheets display exceptional kinetic metrics, including a low overpotential of 43 mV at a geometric current density of 10 mA cm2, a small Tafel slope of 36 mV dec1, and long-term stability of 60 h without any current fading. The performance is even comparable to that of the commercial Pt/C electrocatalyst and significantly better than that of the pure VS2 with a typical interlayer gap.

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How are energy and mass connected during the formation of an atom?

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3 years ago

Which of the following groups in the periodic

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Elements of Group 1 and group 2 in the periodic table contain elements so reactive that they are never found in the free state

Explanation:

The metals in group 1 of periodic table consisting of 'alkali metals' which include lithium, potassium, sodium, rubidium, Francium and caesium. They are highly reactive because they have low ionisation energy and larger radius. The group 2 metals consist of 'alkaline earth metals' which include calcium, strontium, barium, beryllium, radium and magnesium. These alkaline earth metal have +2 oxidation number, hence are highly reactive.

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3 years ago

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3 years ago

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4 years ago

n an experiment, 39.26 mL of 0.1062 M NaOH solution was required to titrate 37.54 mL of \ v unknown acetic acid solution to a ph

olasank [31]

Answer:

Molarity: 0.111M

% (w/w): 0.666

Explanation:

The reaction of NaOH with acetic acid (CH₃COOH) is:

NaOH + CH₃COOH → CH₃COO⁻Na⁺ + H₂O

where 1 mole of NaOH reacts per mole of acetic acid producing 1 mole of water and 1 mole of sodium acetate.

As 39.26mL ≡ 0.03926L of 0.1062M are required to titrate the solution of acetic acid. Moles are:

0.03926L × (0.1062mol / L) = 4.169x10⁻³ moles of NaOH. As 1 mole of NaOH reacts per mole of acetic acid:

4.169x10⁻³ moles of CH₃COOH.

Molarity is defined as ratio between moles of substance and volume of solution in liters. Thus, molarity of acetic acid solution is:

4.169x10⁻³ moles of CH₃COOH / 0.03754L = 0.111M

As molar mass of acetic acid is 60g/mol, 4.169x10⁻³ moles weights:

4.169x10⁻³ moles × (60g / mol) = 0.2501 g of acetic acid

Now, assuming density of solution as 1.00g/mL, 37.54mL weights 37.54g.

Thus, percent by weight is:

0.2501g CH₃COOH / 37.54g × 100 = 0.666% (w/w)

8 0

3 years ago