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tatyana61 [14]
3 years ago
13

Convert a density of 7.2 g/ml into the unit kg/L

Chemistry
1 answer:
aivan3 [116]3 years ago
6 0

Unit conversion is a multi-step process, in which division or multiplication by a numeral factor is involved.

Density = 7.2 g/mL    (given)

Since, 1 g = 0.001 kg and

1 mL = 0.001 L

Now, converting 7.2 g/mL to kg/L:

7.2 \frac{g}{mL}\times \frac{1 kg}{1000 g}\times \frac{1000 mL}{1 L}

= 7.2 kg/L.

Hence, density is 7.2 kg/L.

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A solution of H2SO4(aq) with a molal concentration of 4.80 m has a density of 1.249 g/mL. What is the molar concentration of thi
Naddika [18.5K]
Imagine we have <span>mass of solvent 1kg (1000g)
According to that: </span>molality =n(solute) / m(solvent) =\ \textgreater \  4.8m = 4.8mole / 1kg
= 4.8 mole * 98 g/mole = 470g
m(H2SO4) = n(H2SO4)*Mr(H2SO4) =\ \textgreater \=\ \textgreater \  Molarity = 4.8 mole / 1.2 L = 4 M m(H2SO4)  which is =<span>470g

</span><span>m(solution) = m(H2SO4) + m(solvent) = 470 + 1000 = 1470 g
d(solution) = m(solution) / V(solution) =>
=> 1.249 g/mL = 1470 g / V(solution) =></span>
Molarity = n(solute) / V(solution) =\ \textgreater \
5 0
3 years ago
Plz help!!! This is timed!!!
pogonyaev
58.7 %

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7 0
2 years ago
20 POINTS I will give brainliest to whoever answers correctly
Romashka [77]

All organisms need four types of organic molecules: nucleic acids, proteins, carbohydrates and lipids; life cannot exist if any of these molecules are missing.

6 0
2 years ago
What is the percentage of sodium presents in sodium hydrogen carbonate NaHCO3
STatiana [176]

Answer:-

27.38%

Explanation:-

Molecular weight of sodium hydrogen carbonate NaHCO3

= 23 x 1 + 1 x 1 + 12 x 1 + 16 x 3

= 84 gram

Total sodium Na present in NaHCO3 = 23 x 1 = 23 gram

Percentage of sodium present=

Total sodium x 100/ (Total molecular weight)

= 23 x 100 / 84

= 27.38 %

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2 years ago
Ethanol (C2H5OH) is produced from the fermentation of sucrose in the presence of enzymes.
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actual yield of ethanol = 305.0g

molar mass of sucrose = 342g

molar mass of ethanol  =46g

mass of sucrose = 665g

mole of sucrose = mass / molar mass = 665/342

mole of sucrose =1.9 mole

sucrose :  C2H5OH

       1      :  4

     1.9     : 1.9x4 =7.6 mole of C2H5OH are formed

mass (therotical yield ) of C2H5OH= mole x mass

mass (therotical yield ) of C2H5OH= 7.6 x 46 = 349.6g

percent yields of ethanol =  actual /therotical x100

=305/349.6x100 = 87.24 %

6 0
3 years ago
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