Atmospheric
pressure<span>, sometimes also called barometric pressure, is the pressure exerted by the weight of air in
the </span>atmosphere of Earth<span> (or that of another planet)</span>
1 atm is equivalent to = 101325
Pa
= 760 mmHg
= 760 torr
= 1.01325 bar
So 1.23 atm is equal to
= 124629.8 Pa
= 934.8 mmHg
= 934.8 torr
<span>= 1.2462 bar</span>
Answer:
Periodic but not oscillatory
Explanation:
The Orbital motion of the earth around the sun is not an oscillatory motion as it is not a two and Fro motion about a mean position. But it is a periodic motion.
The way to working out the numbers is to increase the measure of HNO3 required by the molarity to discover what number of moles you require: 0.115. You ought to have the capacity to make sense of the recipe weight H is 1, N is 14, O is 16. The result of the quantity of moles duplicated by the recipe weight ought to give an esteem in grams. You can utilize the thickness to change over to a volume of HNO3 to add to the right volume of water.
Answer:
Kc = [CH₄] / [H₂]²
Kp = [CH₄] / [H₂]² * (0.082*T)^-1
Explanation:
Equilibrium constant, Kc, is defined as the ratio of the concentrations of the products over the reactants. Also, each concentration of product of reactant is powered to its coefficient.
<em>Pure solids and liquids are not taken into account in an equilibrium</em>
Thus, for the reaction:
C(s)+ 2H₂(g) ⇌ CH₄(g)
Equilibrium constant is:
<h3>Kc = [CH₄] / [H₂]²</h3>
Now, using the formula:
Kp = Kc* (RT)^Δn
<em>Where R is gas constant (0.082atmL/molK), T is the temperature of the reaction and Δn is difference in coefficients of gas products - coefficients of gas reactants (1 - 2= -1)</em>
Replacing:
<h3>Kp = [CH₄] / [H₂]² * (0.082*T)^-1</h3>
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