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rjkz [21]
3 years ago
11

An unconformity is an __ of rock

Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
3 0

An unconformity is a missing layer of rock, in other words an erosion separating two units of rock.

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How many moles of cesium (Cs) atoms are in 675g Cs?
sweet-ann [11.9K]
The atomic mass of Cs is 132.9. So the mole number of 675 g cesium is 675/132.9 = 5.08 mole. Then the answer should be 5.08 mole.
8 0
4 years ago
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What aspect of metallic bonding is responsible for malleability ductility and conductivity of metals?
ANTONII [103]
Bonds are forces of attractions between atoms formed by the transfer of electrons or sharing of electrons. Metallic bond is a type bond that exist in metallic structures where the atoms of the metals attracts the sea of electrons in the structure.It is these metallic bonds that results to the malleability , ductility and conductivity of metals because in that the sea of electrons makes them conduct electricity. In addition the atoms of metals in the structure are ions which can slide past each other in the sea of electrons.
4 0
3 years ago
By definition, a solution containing a large number of H3O+ ions is best defined as _________.
Vadim26 [7]
A large quantity if hydronium ions indicates an Arrhenius acid.
4 0
3 years ago
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Which of the following is equal to 3.3mm3? A) 3.3 x 10^-6 m^3 B) 3.3 x 10^-9 m^3 C) 3.3 x 10^-6 cm^3 D) 3.3 x 10^-9 cm^3
vazorg [7]
Step 1 - Since 3.3mm^3 = 0.0033cm^3, convert that to 3.3x10^-3 cm^3.

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Step 3 - 0.0000033 = 3.3 x 10 ^-6 m^3, which is your answer choice A.

*if you do not understand, message me and I will go through it more thoroughly!!*

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3 0
3 years ago
In an experiment, 16.8 g of k2so4 was dissolved in 1.00 kg of water to make a solution. the freezing point of the solution was m
Mashutka [201]
Answer is: V<span>an't Hoff factor (i) for this solution is 2,26.
</span>Change in freezing point from pure solvent to solution: ΔT =i · Kf · m.
<span>Kf - molal freezing-point depression constant for water is 1,86°C/m.
</span>m -  molality, moles of solute per kilogram of solvent.
n(K₂SO₄) = 16,8 g ÷ 174,25 g/mol
n(K₂SO₄) = 0,096 mol.
m(K₂SO₄) = 0,096 mol/kg.
ΔT = 0,405°C.
i = 0,405 ÷ (1,86 · 0,096)
i = 2,26.

8 0
3 years ago
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