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iren2701 [21]
3 years ago
6

A test tube filled with water is placed over a funnel filled with water and a green plant called Elodea. When the plant is expos

ed to light, it begins to produce bubbles. The bubbles being produced are most likely-
Chemistry
1 answer:
Stells [14]3 years ago
5 0

Answer: The bubbles produced are most likely due to oxygen.

Explanation:

Photosynthesis is a phenomenon in which green plants containing chlorophyll use sunlight as a source of energy to convert carbon dioxide and water to form glucose and oxygen.

The balanced chemical reaction for photosynthesis is:

6CO_2+6H_2O\rightarrow C_6H_{12}O_6+6O_2

Thus the bubbles produced are most likely due to oxygen.

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If a hydrogen atom and a helium atom have the same kinetic energy:________
Nuetrik [128]

Answer: If a hydrogen atom and a helium atom have the same kinetic energy then the wavelength of the hydrogen atom will be roughly equal to the wavelength of the helium atom.

Explanation:

The relation between energy and wavelength is as follows.

E = \frac{hc}{\lambda}\\

This means that energy is inversely proportional to wavelength.

As it is given that energy of a hydrogen atom and a helium atom is same.

Let us assume that E_{hydrogen} = E_{helium} = E'. Hence, relation between their wavelengths will be calculated as follows.

E_{hydrogen} = \frac{hc}{\lambda_{hydrogen}}    ... (1)

E_{helium} = \frac{hc}{\lambda_{helium}}         ... (2)

Equating the equations (1) and (2) as follows.

E_{hydrogen} = E_{helium} = E'\\\frac{hc}{\lambda_{hydrogen}} = \frac{hc}{\lambda_{helium}} = E'\\\lambda_{helium} = \lambda_{hydrogen} = E'

Thus, we can conclude that if a hydrogen atom and a helium atom have the same kinetic energy then the wavelength of the hydrogen atom will be roughly equal to the wavelength of the helium atom.

7 0
3 years ago
Urea, (NH2)2CO, is a product of metabolism of proteins. An aqueous solution is 37.2% urea by mass and has a density of 1.032 g/m
Feliz [49]

Answer:

The molarity of urea in this solution is 6.39 M.

Explanation:

Molarity (M) is <em>the number of moles of solute in 1 L of solution</em>;  that is

molarity = moles of solute ÷ liters of solution

To calculate the molality, we need to know the number of moles of urea and the volume of solution in liters. We assume 100 grams of solution.

Our first step is to calculate the moles of urea in 100 grams of the solution,

using the molar mass a conversion factor. The total moles of 100g of a 37.2 percent by mass solution is

60.06 g/mol ÷ 37.2 g = 0.619 mol

Now we need to calculate the volume of 100 grams of solution, and we use density as a conversion factor.

1.032 g/mL ÷ 100 g = 96.9 mL

This solution contains 0.619 moles of urea in 96.9 mL of solution. To express it in molarity, we need to calculate the moles present in 1000 mL (1 L) of the solution.

0.619 mol/96.9 mL × 1000 mL= 6.39 M

Therefore, the molarity of the solution is 6.39 M.

4 0
3 years ago
Which is an example of making a quantitative observation?
Elanso [62]

Answer:

A) measuring mass of metal used in a reaction

Explanation:

Quantitive observations is data involving statistics and numerical values.

4 0
2 years ago
Cations are formed from the?
viva [34]

A caption is a positively charged ion. They are formed when an ion loses one or more electrons. Typical it is the loss Of their valence electrons.

4 0
3 years ago
Can somebody help me plz
xxMikexx [17]

Answer:r=1.2 d=2.4

Explanation:

Radius is half the diameter and the diameter is 2.4 m

8 0
3 years ago
Read 2 more answers
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