Therefore, the sentence "A triangle is isosceles if and only if it has two congruent (equal) sides" is <span>biconditionaL</span>
The common ratio of the given geometric sequence is the number that is multiplied to the first term in order to get the second term. Consequently, this is also the number multiplied to the second term to get the third term. This cycle goes on and on until a certain term is acquired. In this item, the common ratio r is,
r = t⁵/t⁸ = t²/t⁵
The answer, r = t⁻³.
The next three terms are,
n₄ = (t²)(t⁻³) = t⁻¹
n₅ = (t⁻¹)(t⁻³) = t⁻⁴
n₆ = (t⁻⁴)(t⁻³) = t⁻⁷
The answers for the next three terms are as reflected above as n₄, n₅, and n₆, respectively.
Answer:
0.90
Step-by-step explanation:
I entered it onto my calculator, but if you'd like an explanation as to how just ask.
Answer:
<h2><DEF = 40</h2><h2><EBF = <EDF = 56</h2><h2><DCF = <DEF =40</h2><h2><CAB = 84</h2>
Step-by-step explanation:
In triangle DEF, we have:
<u>Given</u>:
<EDF=56
<EFD=84
So, <DEF =180 - 56 - 84 =40 (sum of triangle angles is 180)
____________
DE is a midsegment of triangle ACB
( since CD=DA(given)=>D is midpoint of [CD]
and BE = EA => E midpoint of [BA] )
According to midsegment Theorem,
(DE) // (CB) "//"means parallel
and DE = CB/2 = FB =CF
___________
DEBF is a parm /parallelogram.
<u>Proof</u>: (DE) // (FB) ( (DE) // (CB))
AND DE = FB
Then, <EBF = <EDF = 56
___________
DEFC is parm.
<u>Proof</u>: (DE) // (CF) ((DE) // (CB))
And DE = CF
Therefore, <DCF = <DEF =40
___________
In triangle ACB, we have:
<CAB =180 - <ACB - <ABC =180 - 40 - 56 =84(sum of triangle angles is 180)

Function:(7,-4), (0,9), (2,-2)
(-6,5),(-5,6), (8,2)
(2,3),(6,-5),(-1,3)
Not a function:(0,3),(0,7),(4,0)
(1,9),(-3,-2),(1,-4)