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sergij07 [2.7K]
3 years ago
15

Chord RS intersects chord Tu at point C. The length of TC is 3 times the length of CU. Find the length of TC. If necessary,

Mathematics
2 answers:
Snowcat [4.5K]3 years ago
7 0

Answer:

D

Step-by-step explanation:

D

Amanda [17]3 years ago
7 0

Answer:

C) 24

Step-by-step explanation:

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Therefore, the sentence "A triangle is isosceles if and only if it has two congruent (equal) sides" is <span>biconditionaL</span>
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The common ratio of the given geometric sequence is the number that is multiplied to the first term in order to get the second term. Consequently, this is also the number multiplied to the second term to get the third term. This cycle goes on and on until a certain term is acquired. In this item, the common ratio r is,

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63/40 divided by 70/44
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0.90

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Please help me as fast as you can. thanks
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Answer:

<h2><DEF = 40</h2><h2><EBF = <EDF = 56</h2><h2><DCF = <DEF =40</h2><h2><CAB = 84</h2>

Step-by-step explanation:

In triangle DEF, we have:

<u>Given</u>:

<EDF=56

<EFD=84

So, <DEF =180 - 56 - 84 =40 (sum of triangle angles is 180)

____________

DE is a midsegment of triangle ACB

( since CD=DA(given)=>D is midpoint of [CD]

and BE = EA => E midpoint of [BA] )

According to midsegment Theorem,

(DE) // (CB) "//"means parallel

and DE = CB/2 = FB =CF

___________

DEBF is a parm /parallelogram.

<u>Proof</u>: (DE) // (FB) ( (DE) // (CB))

AND DE = FB

Then, <EBF = <EDF = 56

___________

DEFC is parm.

<u>Proof</u>: (DE) // (CF) ((DE) // (CB))

And DE = CF

Therefore, <DCF = <DEF =40

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In triangle ACB, we have:

<CAB =180 - <ACB - <ABC =180 - 40 - 56 =84(sum of triangle angles is 180)

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